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nadezda [96]
4 years ago
8

How do I factor this problem?2y2(y+7)+(y+7)

Mathematics
1 answer:
Naya [18.7K]4 years ago
8 0
First you distribute the 2y^2 into (y + 7). 2y^2 x y= 2y^3 and 2y^2 x 7= 14y^2. The extra (y + 7) can't be added or multiplied by anything because you can't add y with different exponents. Answer is 2y^3 + 14y^2 + y + 7.
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Make a table of values for the function rule. then graph the function. y=-x²+4​
lakkis [162]

Answer:

check the attached picture

Step-by-step explanation:

Given function is y=-x^2+4.

Now we need to make a table of values for the function rule then graph the function.

We are free to plug any values of x like -3,-2,-1,0,1,2,3,... etc becaues domain of polynomial function is all real numbers.

Let's plug x=1 into given function to find the y-value

y=-x^2+4

y=-(1)^2+4

y=-1+4

y=3

Hence the first point is (1,3).

Same way we can find few more points to complete the table then graph those points and connect them to get the final graph.

x y

-2 8

-1 5

0 4

1 5

2 8

5 0
4 years ago
Lyla took a total of 16 quizzes over the course of 4 weeks. After attending 8 weeks of school this quarter, how many quizzes wil
just olya [345]
32 quizzes. If you make a proportion of quiz/weeks it would be 16/4 = x/8. Multiply by 2.
3 0
3 years ago
Very important question ☺️​
steposvetlana [31]

Answer:

130° is the correct answer

∠QPR=80°

∠PQR+∠QPR+∠QRP=180°

∠PQR+∠QRP=100°

2(x+y)=100°

x+y=50°

So, in △QOR

x+y+∠QOR=180°

∴∠QOR=180°−50°

=130°

4 0
3 years ago
Read 2 more answers
A regular hexagon is inscribed in a circle and another regular hexagon is circumscribed about the same circle. What is the ratio
Anna007 [38]

4/3 of the area of the larger hexagon to the area of the smaller hexagon

Let the sides of the interior hexagon be 2 cm long, then this hexagon is made up of 6 equilateral triangles of side = 2.

The area of this hexagon = 6 * 1 * sqrt3 = 6 sqrt3 ( as the triangle is made up of 2 60-30-90 triangles)

The exterior hexagon is made up of 6 equilateral triangles with altitude 2 and the area = 6 * 2 * (2 / sqrt3 ) = 24 / sqrt3

area exterior hex / interior hex = 24 / sqrt3 * 1 / 6sqrt3 = 24/18

= 4/3

Required ratio = 4/3 answer

Learn more about Equations:

brainly.com/question/16450098

#SPJ4

3 0
2 years ago
A frame is 6in tall and 8 in wide. What if it was reduced to a width of 4in then how tall will it be
kkurt [141]

Answer:

  3 in

Step-by-step explanation:

Apparently, we are to assume that the height and width are proportional:

  height/width = (6 in)/(8 in) = (new height)/(4 in)

Multiplying by 4 in will tell us the new height:

  new height = (4 in)(6/8) = 3 in

The reduced frame will be 3 inches tall.

6 0
3 years ago
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