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Monica [59]
3 years ago
8

What is the area of 2 inches by 1.5inches

Mathematics
1 answer:
Alla [95]3 years ago
4 0
2 x 1.5 = 3 inches

Hope this helps
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|\Omega|=12\cdot11=132\\ |A|=5\cdot4=20\\\\ P(A)=\dfrac{20}{132}=\dfrac{5}{33}

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Identify all of the transformation effects on the graph of the function f(x) = x when f(x) is replaced with -f(x + 4) - 6.
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Answer: B,C E put as brainliest

Step-by-step explanation:

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We can see if the first two options are correct. The first one is eliminated because when x is 2, y is 5 and there is not a different of 5, only 3. This could make you think that the second option is the right answer, but when x is 1, y is 6 and the difference is 5, not 3. 
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Two part-time instructors are hired by the Department of Statistics and each is assigned at random to teach a single course in p
scZoUnD [109]

Answer:

The probability that they will teach different courses is \frac{2}{3}.

Step-by-step explanation:

Sample space is a set of all possible outcomes of an experiment.

In this case we will write the sample space in the form (x, y).

Here <em>x</em> represents the course taught by the first part-time instructor and <em>y</em> represents the course taught by the second part-time instructor.

Denote every course by their first letter.

The sample space is as follows:

S = {(P, P), (P, I), (P, S), (I, P), (I, I), (I, S), (S, P), (S, I) and (S, S)}

The outcomes where the the instructors will teach different courses are:

s = {(P, I), (P, S), (I, P),(I, S), (S, P) and (S, I)}

The probability of an events <em>E</em> is the ratio of the number of favorable outcomes to the total number of outcomes.

P(E)=\frac{n(E)}{N}

Compute the probability that they will teach different courses as follows:

P(\text{Different courses})=\frac{n(s)}{n(S)}=\frac{6}{9}=\frac{2}{3}

Thus, the probability that they will teach different courses is \frac{2}{3}.

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3 years ago
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