Question

The axis of symmetry for the graph of the function f(x) = 3x2 + bx + 4 is x = . What is the value of b?

Answer 1

Answer:

b =-9

Step-by-step explanation:

Given is an equation of a parabola

$f(x) = 3x^{2} +bx+4$

This is a parabola open up

Axis of symmetry is given as x = 3/2

Hence parabola would have equation of the form

$f(x) = a(x-\frac{3}{2} )^2+k$

$f(x) = ax^2-2ax(\frac{3}{2} )+\frac{9a}{4} +k$

Compare this with the given equation

Equate the coefficient of x square to get

a =3

Equate coefficient of x to get

-3a = b

Or b=-3(3) = -9

Hence value of b =-9

Answer 2

the correct answer is -9

The axis of symmetry for the graph of the function f(x) = 3x2 + bx + 4 is x = . What is the value of b?

⇒ -9

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