<h3><u>Answer:</u></h3>
<h3>
<u>Solution:</u></h3>
We are given that the arithmetic progression is defined by :
➝ 2n + 1
<em>Therefore, </em>
- <u>For </u><u>first </u><u>term</u>
➙ n = 1
➝ 2 × 1 + 1
➝ 2 + 1
➝ 3
- <u>For </u><u>second </u><u>term</u>
➙ n = 2
➝ 2 × 2 + 1
➝ 4 + 1
➝ 5
- <u>Common </u><u>difference</u>
➙ 2nd term - 1st term
➝ 5 - 3
➝ 2
<h3><u>More </u><u>information</u><u>:</u></h3>
- The difference between the successive term and the preceding term is the difference of an arithmetic progression. It is always same for the same arithmetic progression.
Answer:
uhh, look it up
Step-by-step explanation:
Answer: 29
explanation: you add 1 to get 2, you then add 2 to get 4, then 3 to get to 7, then 4 to get to 11, then 5 to get to 16, then 6 to get to 22, then 7 to get to 29
F(4) value is 6.
I believe it would work like this:
f(x) is being turned into f(4), so 4 would equal x. Put 4 into the equation 3x-6, and you get 12-6, which gives you 6. So the value of f(4) is 6. I hope this helps!
This is how you would solve the question.
