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polet [3.4K]
3 years ago
13

What is x+61=45+85-180

Mathematics
2 answers:
elena-14-01-66 [18.8K]3 years ago
5 0
The answer would be -11 :))
Alekssandra [29.7K]3 years ago
3 0

Answer: x = - 111

Step-by-step explanation:

  1. Add the like terms on the right side of the equation. 45 + 85 = 130. 130 - 180 = - 50. The equation simplifies to x + 61 = - 50
  2. Subtract 61 on both sides. x = - 111
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The formula for computing the feet is .
nexus9112 [7]

Answer:

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Step-by-step explanation:

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8 0
3 years ago
The profit that a vendor makes per day by selling x elephant ears is given by the function P(x)= -0.004x^2+3.2x-200. Find the nu
dezoksy [38]

Answer:

The number of elephant ears that must be sold to maximize profit is 400.

Step-by-step explanation:

Given that,

The profit that a vendor makes per day is given by

P(x)= - 0.004x² +3.2 x -200

where x is number of elephant ears.

P(x)= - 0.004x² +3.2 x -200

Differentiating with respect to x

P'(x)= - 0.008x+3.2

Again differentiating with respect to x

P''(x) = -0.008

For maximum or minimum P'(x)=0

- 0.008x+3.2=0

⇒0.008x=3.2

\Rightarrow x=\frac{3.2}{0.008}

⇒ x = 400

P''(x)|_{x=400} = -0.008

Since at x=400, P''(x)<0, the profit is maximize.

P(400) = -0.004×400²+3.2×400-200

          =440

The number of elephant ears that must be sold to maximize profit is 400.

3 0
3 years ago
The probability that an American CEO can transact business in a foreign language is .20. Twelve American CEOs are chosen at rand
NNADVOKAT [17]

Answer with Step-by-step explanation:

We are given that

The probability that an American CEO can transact business in  foreign language=0.20

The probability than an American CEO can not transact business in foreign language=1-0.20=0.80

Total number of American CEOs  chosen=12

a. The probability that none can transact business in a foreign language=12C_0(0.20)^0(0.80)^{12}

Using binomial theorem nC_r(1-p)^{n-r}p^r

The probability that none can transact business in a foreign language=\frac{12!}{0!(12-0)!}(0.8)^{12}=(0.8)^{12}

b.The probability that at least two can transact business in a foreign language=1-P(x=0)-p(x=1)=1-((0.8)^{12}+12C_1(0.8)^{11}(0.2))=1-((0.8)^{12}+12(0.8)^{11}}(0.2))

c.The probability that all 12 can transact business in a foreign language=12C_{12}(0.8)^0(0.2)^{12}

The probability that all 12 can transact business in a foreign language=\frac{12!}{12!}(0.2)^{12}=(0.2)^{12}

5 0
3 years ago
Quinzel earns $1254 each month. His total deductions are 20% of his pay. How much is deducted from his pay each month ?
vova2212 [387]

20% = 0.20

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so he has $250.80 deducted every month


7 0
4 years ago
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