What is x+61=45+85-180
2 answers:
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The distance of the spaceship in discuss as in the task content given can be evaluated as; 800miles.
<h3>What is the distance the spaceship travels in 4 minutes?</h3>The distance travelled by the spaceship in discuss can be evaluated by means of the slope of the linear relationship as follows;
Hence it follows from ratios that by observation, the linear relationship has a slope of 200mi/min.
Consequently, we can evaluate the distance travelled after 4 minutes as;
Distance = 200 × 4 = 800mi.
Ultimately, the distance travelled per minute by the spaceship is; 800mi.
Remarks:
600 miles
520 miles
800 miles
1,080 miles
Read more on ratios;
#SPJ1
Answer:
The rug should be 15 ft wide and 28 ft long.
Step-by-step explanation:
I have attached a figure that represents the situation.
The the rug is by
, the width of the strip of floor is
.
We are told that Cynthia can only afford 420 square feet of carpeting; therefore, it must be that
<em>(this says the area of the rug must be 420 square feet)</em>
From the figure we see that
Therefore,
We expand this equation and get:
using the quadratic equation we get two solutions:
since the second solution, namely , is larger than one of the dimensions of the room (is greater than 19 ft) it cannot be the width of the strip; therefore, we take
to be our solution.
Now we find the dimensions of the rug:
The rug is 15 ft wide and 28 ft long.
To simplify this, you would have to turn b^-2 into a positive exponent.
To do this, we have to flip b^-2, which would get rid of the negate from the exponent: -2
3a^4 b^-2 c^3 / b^-2
Then we get the answer:
3a^4 c^3
------------
b^-2
I have a picture to clarify!
I hope this helped, let me know if you don't understand! ^.^
To do this, we have to flip b^-2, which would get rid of the negate from the exponent: -2
3a^4 b^-2 c^3 / b^-2
Then we get the answer:
3a^4 c^3
------------
b^-2
I have a picture to clarify!
I hope this helped, let me know if you don't understand! ^.^