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Degger [83]
3 years ago
9

Jamie's graduation picnic costs $4 for every attendee. At most how many attendees can be there if Jamie budgets a total of $52 f

or his graduation picnic?
Mathematics
1 answer:
bezimeni [28]3 years ago
7 0
He can have 13 attendees
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How many pairs of parallel sides does a trapezoid have?
Roman55 [17]
I think it has 2 pairs of parallel sides
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3 years ago
To the nearest square centimeter, what is the area of the circle below? Use pi = 3.14
Mademuasel [1]

Answer:

radius \:  \: r = 5 \: cm \\ area = \pi {r}^{2}  \\  = 3.14 \times (5) {}^{2}  \\  = 78.5 \:  {cm}^{2}

8 0
3 years ago
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What is the answer for 1 52÷1.9=​
velikii [3]

Answer:

80

Step-by-step explanation:

6 0
3 years ago
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Yochanan walked from home to the bus stop at an average speed of 5 km / h. He immediately got on his school bus and traveled at
kari74 [83]

Answer: 5 km walking and 30 km by bus

Step-by-step explanation:

Yochanan walked from home to the bus stop at an average speed of 5 km / h. He immediately got on his school bus and traveled at an average speed of 60 km / h until he got to school. The total distance from his home to school is 35 km, and the entire trip took 1.5 hours. How many km did Yochanan cover by walking and how many did he cover by travelling on the bus?

walking - 5km/h                                         bus - 60km/h

distance walking - d₁                                 distance bus - d₂

time walking - t₁                                         time bus - t₂

d₁ + d₂ = 35

t₁ + t₂ = 1.5

v = d/t

vwalking = d₁/t₁

5 = d₁/t₁ ⇒ d₁ = 5t₁

vbus = d₂/t₂

60 = d₂/t₂ ⇒ d₂ = 60t₂

d₁ + d₂ = 35 ⇒ 5t₁ + 60t₂ = 35

_________________________

5t₁ + 60t₂ = 35

t₁ + t₂ = 1.5  (*-5)

5t₁ + 60t₂ = 35

-5t₁ -5t₂ = -7.5   (+)

__________________________

55t₂ = 27.5

t₂ = 27.5/55 = 0.5 h

t₁ + t₂ = 1.5 ⇒ t₁ = 1.5 - 0.5 = 1h

d₁ = 5t₁ ⇒ d₁ = 5.1 = 5 km

d₂ = 60t₂ ⇒ d₂ = 30.0.5 = 30 km

6 0
3 years ago
A rectangle's length, x, is 2 meters greater than its width. If the perimeter of the rectangle is greater than 112 meters, what
kotykmax [81]
Assume widthis x-2
perimeter is 2*(width+length)
so 2*(x+x-1)>112
2*(2x-1)>112
4x-2>112
x>28.5
so any length greater than 28.5 will work
6 0
4 years ago
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