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kotegsom [21]
3 years ago
11

Which expression shows the sum of the polynomials with like terms grouped together? 10x^2y+2xy^2-4x^2y

Mathematics
2 answers:
Molodets [167]3 years ago
8 0
<span>first find the similar term, the similar term is x^2y.
10x^2y + 2xy^2- 4x^2y
group together the similar term and place them in a parenthesis
then perform the operation to simplify the expression.
= </span>(10x^2y<span><span> - 4x^2y ) </span>+ 2xy^2
= ( </span><span>6x^2y ) + </span><span>2xy^2
= </span><span>6x^2y </span><span><span>+ <span>2xy^2 is the sum of the polynomial</span></span> </span>





lesya692 [45]3 years ago
7 0

Answer:

I think it is C (-4x^2)+2xy^2+[10x^2y+(-4x^2y)]

Step-by-step explanation:


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Deluxe River Cruises operates a fleet of river vessels. The fleet has two types of vessels: A type-A vessel has 60 deluxe cabins
bixtya [17]

Answer: It should be used 2 for type-A and 3 for type-B to minimize the cost.

Step-by-step explanation: As it is stipulated, <u>x</u> relates to type-A and y to type-B.

Type-A has 60 deluxe cabins and B has 80. It is needed a minimum of 360 deluxe cabins, so:

60x + 80y ≤ 360

For the standard cabin, there are in A 160 and in B 120. The need is for 680, so:

160x + 120y ≤ 680

To calculate how many of each type you need:

60x + 80y ≤ 360

160x + 120y ≤ 680

Isolating x from the first equation:

x = \frac{360 - 80y}{60}

Substituing x into the second equation:

160(\frac{360 - 80y}{60}) + 120y = 680

-3200y+1800y = 10200 - 14400

1400y = 4200

y = 3

With y, find x:

x = \frac{360 - 80y}{60}

x = \frac{360 - 80.3}{60}

x = 2

To determine the cost:

cost = 42,000x + 51,000y

cost = 42000.2 + 51000.3

cost = 161400

To keep it in a minimun cost, it is needed 2 vessels of Type-A and 3 vessels of Type-B, to a cost of $161400

8 0
2 years ago
Two passenger train, A and B, 450 km apart, star to move toward each other at the same time and meet after 2hours.
likoan [24]

Let v be the speed of train A, and let's set the origin in the initial position of train A. The equations of motion are

\begin{cases}s_A(t) = vt\\s_B(t) = -\dfrac{8}{7}vt+450\end{cases}

where s_A,\ s_B are the positions of trains A and B respectively, and t is the time in hours.

The two trains meet if and only if s_A=s_B, and we know that this happens after two hours, i.e. at t=2

\begin{cases}s_A(2) = 2v\\s_B(2) = -\dfrac{16}{7}v+450\end{cases}\implies 2v = -\dfrac{16}{7}v+450

Solving this equation for v we have

2v = -\dfrac{16}{7}v+450 \iff \dfrac{30}{7}v=450 \iff v=\dfrac{450\cdot 7}{30} = 105

So, train A is travelling at 105 km/h. This implies that train B travels at

105\cdot \dfrac{8}{7} = 15\cdot 8=120 \text{ km/h}

5 0
2 years ago
What is the missing angle?
murzikaleks [220]

a straight line = 180 degrees

 so the missing angle is 180 - 130 = 50 degrees

8 0
3 years ago
Read 2 more answers
Please help me!!! :(
PSYCHO15rus [73]

Answer:

15.75x^{10}y^{19}

Step-by-step explanation:

To find the 5th term in the expansion, we first will need to apply the binomial theorem. I have attached an image of the binomial theorem formula due to not being able to type it.

After applying the binomial theorem and simplifying, you should get:

512x^{18}y^{27}-576x^{16}y^{25}+288x^{14}y^{23}-84x^{12}y^{21}+\frac{63x^{10}y^{19}}{4}-\frac{63x^8y^{17}}{32}+\frac{21x^6y^{15}}{128}-\frac{9x^4y^{13}}{1024}+\frac{9x^2y^{11}}{32768}-\frac{y^9}{262144}

Our 5th term here is: \frac{63x^{10}y^{19}}{4} which is equal to 15.75x^{10}y^{19}

~Hope this helps! Sorry if my answer is confusing at all, it's pretty difficult to explain.~

4 0
2 years ago
Can someone help???​
inn [45]

Answer:

help is for the weak as said my I, the one true burnt chicken nugget

Step-by-step explanation:

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