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Vedmedyk [2.9K]
3 years ago
6

What is the interquartile Range for the following data set? {5,6,7,3,9,8,3,1,6,7,7}

Mathematics
1 answer:
mrs_skeptik [129]3 years ago
8 0
To find the interquartile range of the data, you get both quartile one (1) and two (2) and subtract the larger number from the lower number.

Q3 - Q1 = Interquartile range

Your answer, in turn, would be... 
4

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List two properties for each polygon in the coordinate grids?
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4 years ago
Engineers at a large automobile manufacturing company are trying to decide whether to purchase brand A or brand B tires for the
andre [41]

Answer:

s_p =\sqrt{\frac{(12 -1)(5100)^2 +(12-1)(5900)^2}{12 +12 -2}}=5514.526

t=\frac{(37900-39800)-0}{5514.526\sqrt{\frac{1}{12}+\frac{1}{12}}}}=-0.844  

p_v =2*P(t_{22}  

Comparing the p value with a significance level for example \alpha=0.1 we see that p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can conclude that the true means are not significantly different.  

Step-by-step explanation:

Data given and notation

\bar X_{A}=37900 represent the mean for A

\bar X_{B}=39800 represent the mean for B

s_{A}=5110 represent the sample standard deviation for A

s_{B}=5900 represent the sample standard deviation for B

n_{A}=12 sample size for the group A  

n_{B}=12 sample size for the group B

\alpha Significance level provided  

t would represent the statistic (variable of interest)  

Concepts and formulas to use  

We need to conduct a hypothesis in order to check if the means are equal or not, the system of  hypothesis would be:  

Null hypothesis:\mu_{A}-\mu_{B}= 0  

Alternative hypothesis:\mu_{A} - \mu_{B}\neq 0  

We don't have the population standard deviation's but we assume that the population deviation is equal for both populations, so we can apply a t test to compare means, and the statistic is given by:  

t=\frac{(\bar X_{A}-\bar X_{B})-\Delta}{s_p\sqrt{\frac{1}{n_{A}}+\frac{1}{n_{B}}}} (1)  

Where s_p represent the standard deviation pooled given by:

s_p =\sqrt{\frac{(n_A -1)s^2_A +(n_B -1)s^2_B}{n_A +n_B -2}}

s_p =\sqrt{\frac{(12 -1)(5100)^2 +(12-1)(5900)^2}{12 +12 -2}}=5514.526

t-test: Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other.  

With the info given we can replace in formula (1) like this:  

t=\frac{(37900-39800)-0}{5514.526\sqrt{\frac{1}{12}+\frac{1}{12}}}}=-0.844  

P value  

We need to find first the degrees of freedom given by:

df=n_A +n_{B}-2=12+12-2=22

Since is a two tailed test the p value would be:  

p_v =2*P(t_{22}  

Comparing the p value with a significance level for example \alpha=0.1 we see that p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can conclude that the true means are not significantly different.  

6 0
4 years ago
Help please algebra
soldi70 [24.7K]
B, C, E, F  are your answer

hope this helps
3 0
3 years ago
What is the answer to this problem
Anarel [89]
The answer is B 4/5.

Hope this helps
7 0
3 years ago
What is x if 1/4x = 9?
kipiarov [429]

Answer:

x is 36

Step-by-step explanation:

the way to find out is 1/4 multiplied by what gives you 9. 9 divided by 1/4 is 36. 36 1/4's gives you 9.

4 0
2 years ago
Read 2 more answers
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