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erma4kov [3.2K]
2 years ago
12

Can any one help me on this? Please thank you

Mathematics
1 answer:
nignag [31]2 years ago
5 0
The area of a triangle is base length x height then divide all by 2, 
so 12 x 10 /2
=60 ft²
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The binomial 5x – 4 is a factor of 10x2 – 23x + 12. What is the other factor?
SVETLANKA909090 [29]
Method\ 1^o\\10x^2-23x+12=(5x-4)(ax+b)\\\\10x^2-23x+12=5ax^2+5bx-4ax-4b\\\\10x^2-23x+12=5ax^2+(5b-4a)x-4b\\\\therefore\\\\  \begin{array}{ccc}(1)\\(2)\\(3)\end{array}\left\{\begin{array}{ccc}5a=10\\5b-4a=-23\\-4b=12\end{array}\right\\\\(1)\ divide\ both\ sides\ by\ 5\to a=2\\(3)\ divide\ both\ sides\ by\ (-4)\to b=-3\\check\\subtitute\ the\ values\ of\ "a"\ and\ "b"\ to\ (2):\\5\cdot(-3)-4\cdot2=-15-8=-23\ /correct/\\\\Answer:\boxed{2x-3}


Method\ 2^o\\10x^2-23x+12=10x^2-8x-15x+12\\=2x\cdot5x-2x\cdot4-3\cdot5x-3\cdot(-4)\\=2x(5x-4)-3(5x-4)=(5x-4)\boxed{(2x-3)}
6 0
3 years ago
Find the area of a triangle whose sides are 3cm,6cm and 7cm
nadya68 [22]

Answer:

See below

Step-by-step explanation:

It is NOT  a RIGHT triangle so you <u>cannot use</u>   1/2 b * h

 but you can use Heron's Formula

Area = sqrt( s (s-a)(s-b)(s-c) )

s = semi- perimeter =   (3+6+7)/2 = 8

Area = sqrt ( 8 ( 8-3)(8-6)(8-7) )   = sqrt ( 80) = 8.9 cm^2

4 0
1 year ago
What solid figure has eight vertices?
ahrayia [7]
Rectangular prism the two square on the end have 4 vertices each
3 0
2 years ago
Suppose that X is a random variable with mean 30 and standard deviation 4. Also suppose that Y is a random variable with mean 50
Vladimir79 [104]

Answer:

a) Var[z] = 1600

    D[z] = 40

b) Var[z] = 2304

    D[z] = 48

c) Var[z] = 80

    D[z] = 8.94

d) Var[z] = 80

    D[z] = 8.94

e) Var[z] = 320

    D[z] = 17.88

Step-by-step explanation:

In general

V([x+y] = V[x] + V[y] +2Cov[xy]

how in this problem Cov[XY] = 0, then

V[x+y] = V[x] + V[y]

Also we must use this properti of the variance  

V[ax+b] = a^{2}V[x]

and remember that

standard desviation = \sqrt{Var[x]}

a) z = 35-10x

   Var[z] = 10^{2} Var[x] = 100*16 = 1600

   D[z] = \sqrt{1600} = 40

b) z = 12x -5

   Var[z] = 12^{2} Var[x] = 144*16 = 2304

   D[z] = \sqrt{2304} = 48

c) z = x + y

   Var[z] =  Var[x+y] = Var[x] + Var[y] = 16 + 64 = 80

   D[z] = \sqrt{80} = 8.94  

d) z = x - y

   Var[z] =  Var[x-y] = Var[x] + Var[y] = 16 + 64 = 80

   D[z] = \sqrt{80} = 8.94

e) z = -2x + 2y

   Var[z] = 4Var[x] + 4Var[y] = 4*16 + 4*64 = 320

  D[z] = \sqrt{320} = 17.88

   

7 0
3 years ago
Is the following relation a function? Two circles are shown, one labeled x and the other labeled y. The x circle contains the nu
Allushta [10]

Answer:

i  believe that it is a function.

Step-by-step explanation:

you do not have any of the exact same numbers with arrows ot one another.

5 0
3 years ago
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