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2 years ago

Can any one help me on this? Please thank you

Mathematics

1 answer:

nignag [31]2 years ago

5 0

The area of a triangle is base length x height then divide all by 2,
so 12 x 10 /2
=60 ft²

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A study on the latest fad diet claimed that the amounts of weight lost by all people on this diet had a mean of 23.2 pounds and

erica [24]

Answer:

The standard deviation of the sampling distribution of sample means would be 0.8186.

Step-by-step explanation:

We are given that

Mean of population=23.2 pounds

Standard deviation of population=6.6 pounds

n=65

We have to find the standard deviation of the sampling distribution of sample means.

We know that standard deviation of the sampling distribution of sample means

= $\frac{\sigma}{\sqrt{n}}$

Using the formula

The standard deviation of the sampling distribution of sample means

= $\frac{6.6}{\sqrt{65}}$

$=0.8186$

Hence, the standard deviation of the sampling distribution of sample means would be 0.8186.

3 0

3 years ago

Can someone help me with this and show the step to solving it

anyanavicka [17]

Answer:x = 9/16

Step-by-step explanation:

2x + 3 = 6x - 4

First you gotta get rid of the divided by 3

2x / 3 = 2/3x and 3 / 3 = 1

Now you have

2/3x + 1 = 6x - 4

Second you have to get rid of the 2/3x on the left side

2/3x + 1 = 6x - 4

-2/3x -2/3x

1 = 5 1/3x - 4

Third you have to get rid of the -4

1 = 5 1/3x - 4

-4 -4

-3 = 5 1/3x

Fourth you have to divide by 5 1/3

-3 = 5 1/3x

/ 5 1/3 / 5 1/3

x = 9/16

3 0

3 years ago

s = 6t² + 3t + 7, 0 ≤ t ≤ 2 Find the body's displacement and average velocity for the given time interval.

Lapatulllka [165]

Answer:

I hope I help you

...........

4 0

2 years ago

Answer this question please and thank you

WITCHER [35]

39.273 ------> 39

- 8.58 ------> 9

----------------------

30.693 -----> 30

4 0

3 years ago

Read 2 more answers

X^lg(x)=100^x find x

Wittaler [7]

$x^lg(x)=100^x$

$X^lg(x)=100^x:x$ $|Solve \ for \ x|$

$|Use \ logarithms \ of \ both \ sides \ of \ the \ base \ 10|

$

$lg (x ^ lg (x)) = lg (100x)

$

$lg ^ 2 (x) = 2 + lgx$

$lg 2 ^ x-lg x -2 = 0$

$lg x = 2 x = 100$

$lg x = -1 x = \dfrac{1}{10} = 0.1$

3 0

3 years ago