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wolverine [178]
3 years ago
15

Plz help!!!!!!!!!!!!!!

Mathematics
2 answers:
olganol [36]3 years ago
3 0

the answer is 12 place 2 , 4.5,12 In place of X and solve

insens350 [35]3 years ago
3 0

Answer:   x = 12

<u>Step-by-step explanation:</u>

.\qquad \qquad \qquad \qquad \qquad \sqrt{2x+1}-4=1\\\\\text{Add 4 to both sides:}\quad \sqrt{2x+1}=5\\\\\text{Square both sides:}\quad \quad 2x+1=25\\\\\text{Subtract 1 from both sides:}\quad 2x=24\\\\\text{Divide both sides by 2:}\qquad \quad x = 12

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denis-greek [22]

Answer:

2(2−1)

Step-by-step explanation:

4−2

Grouping

Common factor

4−2

2(2−1)

Solution

2(2−1)

7 0
2 years ago
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Area of a regular octagon with radius 8
bixtya [17]

Step-by-step explanation:

Area of the octagon = 2(1+√2)8=309.02 units

3 0
3 years ago
Please help me I need help please​
MakcuM [25]

Answer:

p = 4

Step-by-step explanation:

Given equation:

x^2+(p-3)y^2-4x+6y-16=0

<u>Standard equation of a circle:</u>

(x-a)^2+(y-b)^2=r^2

(where (a,b) is the centre of the circle, and r is the radius)

If you expand this equation, you will see that the coefficient of y^2 is always one.

Therefore, p-3=1

\implies p=1+3=4

<u>Additional information</u>

To rewrite the given equation in the standard form:

\implies x^2+y^2-4x+6y-16=0

\implies x^2-4x+y^2+6y=16

\implies (x-2)^2-4+(y+3)^2-9=16

\implies (x-2)^2+(y+3)^2=16+4+9

\implies (x-2)^2+(y+3)^2=29

So this is a circle with centre (2, -3) and radius √29

3 0
2 years ago
Graph the following equations<br> - y = 2 x - 1
zalisa [80]

Answer:

f(x)= 1 - 2x

Step-by-step explanation:

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3 years ago
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you can make it into an improper fraction if you want but there is no need for this problem

steps

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answer:5 1/2 or 5 2/4

(it is better simplified)

8 0
2 years ago
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