What percentage of rupees 20 is rupees 12?
1 answer:
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Answer:
Step-by-step explanation:
We are factoring
So:
((2•5^2x^2) + 485x) - 150
Pull like factors :
50x^2 + 485x - 150 = 5 • (10x^2 + 97x - 30)
Factor
10x^2 + 97x - 30
Step-1: Multiply the coefficient of the first term by the constant 10 • -30 = -300
Step-2: Find two factors of -300 whose sum equals the coefficient of the middle term, which is 97.
-300 + 1 = -299
-150 + 2 = -148
-100 + 3 = -97
-75 + 4 = -71
-60 + 5 = -55
-50 + 6 = -44
-30 + 10 = -20
-25 + 12 = -13
-20 + 15 = -5
-15 + 20 = 5
-12 + 25 = 13
-10 + 30 = 20
-6 + 50 = 44
-5 + 60 = 55
-4 + 75 = 71
-3 + 100 = 97
Step-3: Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -3 and 100
10x^2 - 3x + 100x - 30
Step-4: Add up the first 2 terms, pulling out like factors:
x • (10x-3)
Add up the last 2 terms, pulling out common factors:
10 • (10x-3)
Step-5: Add up the four terms of step 4:
(x+10) • (10x-3)
Which is the desired factorization
Thus your answer is
Answer: 7234.56 cm
V = π r³
V = (3.14) (12)³
V = 7234.56 cm Answer...
Hope that helps...
Answer:
1) Option c) is correct ie., 5 real and o non-real
2) Option b) is correct ie., (4, ,
, 2,2)
Step-by-step explanation:
Given polynomial function is
To find zeros equate f(x) to zero ie.,
By synthetic division
| 1 0 -3 0 -2
-1 | 0 -1 1 2 2
|_________________
1 -1 -2 2 0
Therefore x=-1 is a zero
| 1 -1 -2 2
1 | 0 1 0 2
|___________________
1 0 -2 0
x=1 is the zero
and
Option c) is correct ie., 5 real and o non-real
2) Given polynomial function is
To find zeros equate f(x) to zero ie.,
(or)
or
Therefore x=4, of multiplicity of 2 and x=2 multiplicity of 2
Option b) is correct ie., (4, ,
, 2,2)