We have no dimensions to work with. I'll pick some and try and comply with the conditions of the problem.
Suppose you have an object that is 14 by 22 by 27 cm. These three numbers have no common factor so they cannot be reduced any further, which is helpful for this problem.
Find the Volume
Volume
l = 27 cm
w = 14 cm
h = 22 cm
V = 27 *14 * 22
V = 8316 cm^3
Find the surface area
SA = 2*l*w + 2*l*h + 2*w*h
SA = 2*27*14 + 2*27*22 + 2*14*22
SA = 756 + 1188 + 616
SA = 2558
Just looking at these numbers The surface area is about 1/3 of the volume. I don't think this is always true.
Another way to do this is to consider a cube which might give you a more useful result.
s = L = W = H all three dimensions are equal in a cube.
The volume of a cube is s*s*s = s^3
The surface area of a cube is 2*s*s + 2*s*s + 2s*s = 6s^2


That means whatever the side length, the Surface Area to volume = 6/the side length which is kind of an interesting result.
Step-by-step explanation:
7 + y < 12 it can also be written as
7 + y = 12
y = 12 - 7
y = 5
or
y < 5
Hope it will help :)
Answer:
Hazel will have knitted 25 centimeters of the scarf
SOLUTION
Problem Statement
We are told Hazel knits 5 centimeters of scarf every night for 5 nights. We are required to find the length of the scarf Hazel will have knitted after 5 nights.
Solution
We are told Hazel makes 5 centimeters of scarf every night. Thus, for each night up till 5 nights, we just need to add the length of scarf Hazel has made.
Let us count for each night.
Night 1:
Hazel makes 5 centimeters of the scarf.
Night 2:
Hazel makes extra 5 centimeters, which means she has made:

Night 3:
Hazel makes extra 5 centimeters, which means she has made:

NIght 4:
Hazel makes extra 5 centimeters, which means she has made:

NIght 5:
Hazel makes extra 5 centimeters, which means she has made:

Final Answer
Thus, Hazel will have knitted 25 centimeters of the scarf
Answer:
9 is answer . . . . . . . ........

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☆ Now Let's find value of sin A, cos A and tan A,
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- sin A = Perpendicular/Hypotenus =

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- cos A = Base/Hypotenus =

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- tan A = Perpendicular/Base =

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