Answer:
x(t) = 5000*( 1 - e^-kt)
Step-by-step explanation:
Given:
- Total number of students n = 5000
Find:
Differential equation governing the number of students x(t) who have contracted the flu.
Solution:
- Number of non-affected students = (5000 - x)
Hence,
- Rate at which students are infected:
dx / dt = k*(5000 - x )
- separate variables:
dx / (5000 - x ) = k*dt
- Integrate both sides:
- Ln(5000 - x) = kt + C
- Evaluate C for x = 0 @ t = 0
- Ln(5000 - 0) = k*0 + C
C = - Ln(5000)
- The solution to ODE is:
Ln(5000 - x) = -k*t + Ln(5000)
5000 - x = 5000*e^-kt
x(t) = 5000*( 1 - e^-kt)
Answer:
the required equation is y = 2 x + 1
Step-by-step explanation:
by putting the value of x ( 1,3 )
- y = 2 × 1 + 1
- y = 2 + 1
- y = 3
it shows y = 3, hence y = 2x+1 will pass through
( 1, 3 )
by putting the value of x ( -2, -3 )
- y = (-2 × 2) + 1
- y = -4 + 1
- y = -3
it shows y = -3 , hence y = 2x + 1 will pass through ( -2, -3 )
Answer: the answer is 650 miles
Step-by-step explanation: you do 65x10
