The square box is enough to fit the pizza with a diameter of 10 inches inside. Since the area of the square box is more than the area of the pizza, the pizza fits easily in the square box.
<h3>What is the area of the circle and the square?</h3>
The area of the circle is
Ac = πr² = πd²/4 sq. units
Where r is the radius and d is the diameter of the circle.
The area of the square is given by
As = s² sq. units
Where s is the length of the side of a square.
<h3>Calculation:</h3>
It is given that a pizza(in a circular shape) with a diameter d = 10 in is to be placed in a square box of the same length as the diameter of the pizza.
So,
The area of pizza is
Ap = Ac = πd²/4 sq. units
= π(10)²/4
= 25π
= 78.54 sq. in
Then, the area of the square box with the length same as the diameter of the pizza is,
As = d²
= 10²
= 100 sq. in
Since the area of the square is more than the area of the pizza (100 sq. inch > 78.54 sq. inch), the pizza easily fits into the square box.
Learn more about the area of a circle here:
brainly.com/question/15673093
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Answer:
312π mm³
Step-by-step explanation:
Given:
Oblique cone height, h = 14 mm
radius of half sphere = base radius of cone, r = 6 mm
Recall the volume of 1/2 - sphere
= 1/2 x volume of sphere
= 1/2 x (4π/3) r³
= 1/2 x (4π/3) (6)³
= 144π
Also volume of an oblique cone =
=volume of a right cone
= (π/3) r²h
= (π/3) 6²(14)
=168π
Volume of composite figure = 144π + 168π = 312π mm³
i think it will make it smaller due to the base being longer which stretches out the two sides and makes less space inside of the triangle
P(both work) = ((10-3)/10)*((10-3-1)/9) = (7/10)*(6/9) = 42/90
<span>P(at least one does not work) = 1 - P(both work) = 1 - 42/90 = 48/90 = 24/45.</span>
