Answer:
He has 11 quarters
Step-by-step explanation:
* Lets study the information in the problem to solve it
- The value of dimes and quarters is $6.35
- There are dimes and quarters
- The dime = 10 cents
- The quarter = 25 cents
* We must change the money from dollars to cents
∵ $1 = 100 cents
∴ $6.35 = 6.35 × 100 = 635 cents
- The number of dimes = 3 + 3 × number of quarters
* Let number of dimes is D and number of quarter is Q
∴ D = 3 + 3Q
∴ 10D + 25Q = 635
* Substitute the value of D from first equation in the second equation
∴ 10(3 + 3Q) + 25Q = 635 ⇒ open the bracket
∴ 10(3) + 10(3Q) + 25Q = 635
∴ 30 + 30Q + 25Q = 635 ⇒ collect like terms
∴ 30 + 55Q = 635 ⇒ subtract 30 from both sides
∴ 55Q = 605 ⇒ divide both sides by 55
∴ Q = 11
* He has 11 quarters
Answer:
0.00109
Step-by-step explanation:
1.09(10^−3)
=1.09*10^−3
=1.09*
1
/10*10*10
=0.00109
Answer:
1/2
Step-by-step explanation:
1/2
Well, the best way to solve this would involve the Pythagorean theorem.
First, take the length of the hypotenuse (the string in this case) and square it. Do the same to the side length we are given (the kites height above the ground).
We then subtract the squared height from the squared hypotenuse. We should be left with 1,781m.
All we have to do now is find the square root of 1,781m.
Your answer for b is 42.20189569m.
