One factor of f(x) = x3 − 14x2 + 61x − 84 is (x − 7). What are the zeros of the function?
2 answers:
Answer:
7, 4, 3
Step-by-step explanation:
Using Descartes' rule of signs, you can determine there are zero negative real roots. The above answer choice is the only one with no negative zeros listed.
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The count of negative real roots is based on the number of sign changes when the signs of odd-degree terms are reversed. Doing that gives the signs of the terms as - - - -, so there are no changes. That means there are no negative real roots.
A graphing calculator confirms this choice.
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Answer:
Range = (-<em>∞, 5</em>)
Step-by-step explanation:
This is the absolute value function with transformation.
The parent function is f(x) = |x|
This function has a "negative" in front, so it makes it reflect about x axis
The -4 after x makes horizontal translation of 4 units right
the +5 at the end makes the function translate 5 units UP
<em>The graph is shown in the attached picture.</em>
<em>Looking at the graph, we can clearly see the range. The range is the allowed y-values. Hence, we can see that the </em><em>range is -infinity to 5</em>
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<em>answer is not properly given, so i can't choose from the options, but the answer is -∞, 5 to 5</em>
