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3 years ago

Select the correct choices that belong in the blank for the system of equations shown below.

Mathematics

2 answers:

Sergeeva-Olga [200]3 years ago

6 0

Answer:

A. multiplies the second equation by 4

Step-by-step explanation:

Given the simultaneous equation,

24x-39=165...(1)

-6x+13y=-51...(2)

To solve the equation using elimination method to cancel out variable x, first we need to ensure the coefficients of x in both equations are the same value but different signs (since Stacy added the expressions after multiplying) so that they can easily cancel out. To make the coefficient have equal value with different signs, we will multiply the first equation by 1 and multiply the second equation by 4 to have

24x-39=165...(3)

-24x+52y=-204...(3)

Adding the resulting simultaneous equation will cancel out the x variable.

Note that the equation was added due to difference in sign of coefficient ox x (24 and-24).

tensa zangetsu [6.8K]3 years ago

5 0

Answer:

A.)multiplies the second equation; 4

Step-by-step explanation:

when we multiple second equation by 4 we get -24x -52y = 204 and when we add it up with the first equation we x eliminate x.

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3 years ago

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Furkat [3]

Answer:

D) 2, 4, 8, 16, 32

Step-by-step explanation:

We have given four sets of sequence.

And we have to find out which sequence is not an arithmetic sequence.

For this the given sequences should satisfy the value of common difference(d) and Arithmetic Progression formula.

A.P. Formula,

$T_n=a+(n-1)d$

Where $T_n$ = nth term of an A.P.

a = first term of an A.P.

n = number of terms.

d = common difference.

'd' is calculated by subtracting fist term from second term.

$d = second\ term-first\ term$

A) 4, 7, 10, 13, 16

$d = 7-4=3$

$d = 10-7=3$

Here d=3 and 5th term is 16.

So we find out the 5th term by using the formula of A.P. To check whether the sequence is in A.P. or not.

$T_5=4+(5-1)3=4+4\times\ 3=4+12=16$

Here the given sequence fulfills the condition of being in A.P.

Hence the given sequence is an arithmetic sequence.

B) 1, 2, 3, 4, 5

$d =2-1=1$

$d =3-2=1$

Here d=1 and 5th term is 5.

$T_5=1+(5-1)1=1+4=5$

Here the given sequence fulfills the condition of being in A.P.

Hence the given sequence is an arithmetic sequence.

C) 15, 9, 3, -3, -9

$d =9-15=-6$

$d =3-9=-6$

Here d=-6 and 5th term is -9.

$T_5=15+(5-1)-6=15+4\times -6=15+(-24)=-9$

Here the given sequence fulfills the condition of being in A.P.

Hence the given sequence is an arithmetic sequence.

D) 2, 4, 8, 16, 32

$d_1=4-2=2$

$d_2=8-4=4$

Here $d_1=2\ But\ d_2=4$

The common difference between the terms is not same.

In case of $d_1$ .

$T_5=2+(5-1)2=2+4\times 2=2+8=10$

In case of $d_2$ .

$T_5=2+(5-1)4=2+4\times 4=2+16=18$

Here the given sequence does not fulfills the condition of being in A.P.

Hence the given sequence is not an arithmetic sequence.

Hence the correct option is D) 2, 4, 8, 16, 32.

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4 years ago

Which graph shows the solution to the system of linear inequalities?

tangare [24]

Answer:

See below

Step-by-step explanation:

<u>Given system:</u>

y ≥ 2x + 1
y ≤ 2x – 2

The solution is the common area shaded by the inequalities.

The lines are parallel because of same slope.

Both lines are solid because of equal sign in both inequalities.

The first inequality has a y-intercept of 1 and shaded area is to the left of the line since the value of y is greater as x increases.

The second inequality has a y-intercept of -2 and shaded area is to the right of the line since the value of y is greater as x increases.

The matching graph is the second picture (or attached below) and there is no solution.

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Nutka1998 [239]

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Sunny_sXe [5.5K]

Answer:

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Step-by-step explanation:

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