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3 years ago

How many terms are in the expression shown below? 5u 3 v + 3u 2 v 2 + 4uv + 5

Mathematics

1 answer:

Marianna [84]3 years ago

7 0

Answer:

There are four terms of the expression $5u^3v+3u^2v^2+4uv+5$ .

Step-by-step explanation:

The given expression is $5u^3v+3u^2v^2+4uv+5$ .

The first term of this expression is $5u^3v$ .

The second term of this expression is $3u^2v^2$ .

The third term of the expression is $4uv$ .

The fourth term of the expression is $5$ .

Therefore, there are four terms in the given expression.

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Which polynomial represents the sum below?<br> (3x2 + 3) + (3x2 + x + 4)

DIA [1.3K]

Add like terms just like you would anywhere else... $6 x^{2} +x+7$

6 0

3 years ago

you currently have 24 credit hours and a 2.8 gpa you need a 3.0 gpa to get into the college. if you are taking a 16 credit hours

Juliette [100K]

Answer:

$\sum_{i=1}^n w_i *X_i = 2.8*24 = 67.2$

And for this case we want a gpa of 3.0 taking in count that in this semester he/ she is going to take 16 credits so then the new mean would be given by:

$\bar X_f = \frac{\sum_{i=1}^n w_i *X_i+w_f *X_f }{24+16} = 3.0$

And we can solve for $\sum_{i=1}^n w_f *X_f$ and solving we got:

$3.0 *(24+16) =\sum_{i=1}^n w_i *X_i +\sum_{i=1}^n w_f *X_f$

And from the previous result we got:

$3.0 *(24+16) =67.2 +\sum_{i=1}^n w_f *X_f$

And solving we got:

$\sum_{i=1}^n w_f *X_f =120 -67.2= 52.8$

And then we can find the mean with this formula:

$\bar X_2 = \frac{\sum_{i=1}^n w_f *X_f}{16}= \frac{52.8}{16}=16=3.3$

So then we need a 3.3 on this semester in order to get a cumulate gpa of 3.0

Step-by-step explanation:

For this case we know that the currently mean is 2.8 and is given by:

$\bar X = \frac{\sum_{i=1}^n w_i *X_i }{24} = 2.8$

Where $w_i$ represent the number of credits and $X_i$ the grade for each subject. From this case we can find the following sum:

$\sum_{i=1}^n w_i *X_i = 2.8*24 = 67.2$

And for this case we want a gpa of 3.0 taking in count that in this semester he/ she is going to take 16 credits so then the new mean would be given by:

$\bar X_f = \frac{\sum_{i=1}^n w_i *X_i+w_f *X_f }{24+16} = 3.0$

And we can solve for $\sum_{i=1}^n w_f *X_f$ and solving we got:

$3.0 *(24+16) =\sum_{i=1}^n w_i *X_i +\sum_{i=1}^n w_f *X_f$

And from the previous result we got:

$3.0 *(24+16) =67.2 +\sum_{i=1}^n w_f *X_f$

And solving we got:

$\sum_{i=1}^n w_f *X_f =120 -67.2= 52.8$

And then we can find the mean with this formula:

$\bar X_2 = \frac{\sum_{i=1}^n w_f *X_f}{16}= \frac{52.8}{16}=16=3.3$

So then we need a 3.3 on this semester in order to get a cumulate gpa of 3.0

6 0

3 years ago

Classify the figure in as many ways as possible.

Dima020 [189]

The answer is D.

This figure has 4 sides which makes it a quadrilateral.

This figure has 2 sets of parallel sides which makes it a parallelogram.

This figure has 4 equal sides which makes it a rhombus.

This figure has 4 right angles which makes it a rectangle.

And this figure has both 4 equal sides and 4 equal angles which makes it a square.

To make it easier, all squares are: quadrilaterals, parallelograms, rhombuses, rectangles and of course squares.

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3 years ago

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Alinara [238K]

Answer:

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Step-by-step explanation:

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3 years ago

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