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3 years ago

5

How many terms are in the expression shown below? 5u 3 v + 3u 2 v 2 + 4uv + 5

1 answer:

Marianna [84]3 years ago

7 0

Answer:

There are four terms of the expression $5u^3v+3u^2v^2+4uv+5$ .

Step-by-step explanation:

The given expression is $5u^3v+3u^2v^2+4uv+5$ .

The first term of this expression is $5u^3v$ .

The second term of this expression is $3u^2v^2$ .

The third term of the expression is $4uv$ .

The fourth term of the expression is $5$ .

Therefore, there are four terms in the given expression.

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Let r and s be the roots of x^2 - 6x + 2 = 0. Find (r - s)^2.

Sphinxa [80]

Answer: $(r-s)^{2} = 28$

Step-by-step explanation:

$x^{2} -6x+9=-2+9$
$(x-3)^{2}=7$
$(x-3)= -\sqrt{7}$ or $\sqrt{7}$ <-- there's no plus/minus sign.

$(x-3) = -\sqrt{7}$
$x = 3 -\sqrt{7}$ <-- root.

$(x-3) = \sqrt{7}$
$x = 3+\sqrt{7}$ <-- root.

$[(3-\sqrt{7})-(3+\sqrt{7})]^{2}$
$(3-\sqrt{7} -3 - \sqrt{7})^{2}$ <-- don't forget to distribute the negative.
$(-2\sqrt{7})^{2}$
$(4)(7)$
$28$

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Step-by-step explanation:

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Step-by-step explanation:

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2 years ago

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