This can be easily figured out. Check to see what points are on the bottom and that is your answer.
B
Check the picture below, so the circle looks more or less like so, with a radius of 9.
![\textit{circumference of a circle}\\\\ C=2\pi r~~ \begin{cases} r=radius\\[-0.5em] \hrulefill\\ r=9 \end{cases}\implies C=2\pi (9)\implies C\approx 57](https://tex.z-dn.net/?f=%5Ctextit%7Bcircumference%20of%20a%20circle%7D%5C%5C%5C%5C%20C%3D2%5Cpi%20r~~%20%5Cbegin%7Bcases%7D%20r%3Dradius%5C%5C%5B-0.5em%5D%20%5Chrulefill%5C%5C%20r%3D9%20%5Cend%7Bcases%7D%5Cimplies%20C%3D2%5Cpi%20%289%29%5Cimplies%20C%5Capprox%2057)
Part A: B)35
As the angle y° equals to angle 2x°, y=2x.
And the sum of the angle (x+y+5°)and the angle 2x° is 180°.Therefore,
x+y+5°+2x =180°
x+2x+5°+2x=180°
5x+5° =180°
5x =175°
x =35°
Part B: C)110°
As I said, y =2x
And the unlabled angle eaquals to the angle(x+y+5°).
Therefore,
the unabled angle= x+y+5°
=x+2x+5°
=3x+5°
=3(35°)+5°
=110°
2xy + 8y - 8x - 32
2(xy + 4y - 4x - 16)
2(x + 4)(y - 4)
Answer:
what are you trying to find?