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Pie
2 years ago
12

Explain how you can use a quick picture to find 3 x 2.7

Mathematics
2 answers:
viva [34]2 years ago
5 0
Draw three rectangles with three rows each and 10 columns in each row. Fill in the first two rows and seven rectangles in each of the large rectangles.
Pie2 years ago
4 0
We don’t need a quick picture.
Its simple multiplication.
2.7
3 *
———-
7.1

7.1 is final answer
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The perimeter of a rectangle is 400 feet and the length of the rectangle is 3 times the width. find the dimensions of the rectan
bazaltina [42]
Width: x
Length: 3x
Perimeter=x+x+3x+3x=8x
8x=400
x=50
Dimension is 150×50 feet (length × width)
8 0
3 years ago
)) Two tailors, Kristen and Layla, sit down to do some embroidery. Kristen can embroider 5
serious [3.7K]

Answer:

2 hours or less depending on how skilled or how they're felling that day

Step-by-step explanation:

4 0
3 years ago
Consider the function g(x) = (x-e)^3e^-(x-e). Find all critical points and points of inflection (x, g(x)) of the function g.
Elden [556K]

Answer:

The answer is "cirtical\  points \ (x,g(x))\equiv  (e,0),(e+3,\frac{27}{e^3})"

Step-by-step explanation:

Given:

g(x) = (x-e)^3e^{-(x-e)}

Find critical points:

g(x) = (x-e)^3e^{(e-x)}

differentiate the value with respect of x:

\to g'(x)= (x-e)^3 \frac{d}{dx}e^{e-r} +e^{e-r}  \frac{d}{dx}(x-e)^3=(x-e)^2 e^{(e-x)} [-x+e+3]

critical points g'(x)=0

\to (x-e)^2 e^{(e-x)} [e+3-x]=0\\\\\to e^{(e-x)}\neq 0 \\\\\to (x-e)^2=0\\\\ \to [e+3-x]=0\\\\\to x=e\\\\\to x=e+3\\\\\to x= e,e+3

So,

The critical points of (x,g(x))\equiv  (e,0),(e+3,\frac{27}{e^3})

7 0
3 years ago
Public Service Announcement : For anyone that continues to delete my answers even if their educational/ or correct can STAY MAD.
lozanna [386]

Answer:

You tell them

Step-by-step explanation:

Never stop being postive

6 0
3 years ago
Read 2 more answers
According to the graph, what is the value of the constant in the equation below?
dedylja [7]

Answer:0.4

Step-by-step explanation:

I believe it is B

3 0
3 years ago
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