What is 795,431 rounded to the nearest ten thousand?

Mathematics

1 answer:

nadya68 [22]3 years ago

8 0

I’m pretty sure the answer would be A because the 5 makes the 9 round up to ten and then the 7 becomes an 8.

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Someone help me please

garri49 [273]

Answer:

42 seats

Step-by-step explanation:

This represents an arithmetic progression with the first term of a = 15 and common difference of d = 3.

The tenth row is the 10th term:

aₙ = a + (n - 1)d

The row 10 has:

a₁₀ = 15 + 9*3 = 15 + 27 = 42 seats

7 0

2 years ago

Read 2 more answers

What is the value of the correlation coefficient r of the data set?

enyata [817]

The correct option will be: C) 0.84

Explanation

Formula for Correlation coefficient :

$r= \frac{n(\Sigma xy)-(\Sigma x)(\Sigma y)}{\sqrt{[n\Sigma x^2-(\Sigma x)^2][n\Sigma y^2-(\Sigma y)^2]}}$

First, for each point(x, y), we need to calculate x², y² and xy .

Then, we will find sum all x, y, x², y² and xy, which gives us Σx, Σy, Σx², ∑y² and Σxy

(Please refer to the attached image for the table )

Here we got, ∑x = 44 , ∑y = 183 , ∑x² = 362 , ∑y² = 6575 and ∑xy = 1480

'n' is the total number of data set, which is 7 here.

So, plugging those values into the above formula..........

$r= \frac{n(\Sigma xy)-(\Sigma x)(\Sigma y)}{\sqrt{[n\Sigma x^2-(\Sigma x)^2][n\Sigma y^2-(\Sigma y)^2]}}\\ \\ r=\frac{7(1480)-(44)(183)}{\sqrt{[7(362)-(44)^2][7(6575)-(183)^2]}}\\ \\ r=\frac{10360-8052}{\sqrt{(598)(12536)}}\\ \\ r=\frac{2308}{\sqrt{7496528}}\\ \\ r=0.84$