Answer:
(A) 7.5 %
(B) 3.75 %
(C) 2.5%
(D) 0.625 %
Step-by-step explanation:
We have given effective rate of interest r = 7.5%
(a) Annual rate of interest will be equal to 7.5 %
(B) As we know that 1 year = 12 months
And interest is compounded semiannually
1 semiannual = 6 months
So semiannual rate of interest will be equal to
%
(c) 1 quarter = 4 month
So number of period in an year = 3
So rate of interest quarterly
%
(D) Amount when amount is compounded monthly '
So number of period in an year = 12
So rate of interest
%
Ok so lets start off with calculating the percentage. We have 240 cards so lets find 25% of them so lets use 240 times .25 we get 60 cards then take away 240 - 60 = 180. Next we do the 30% so 240 times .30 would be 72 so take away 180 from 72 thats 108. So there are 108 Houston Astros Cards.
Answer:
9^-3/9^12
Step-by-step explanation:
Answer:
The probability that the sample will contain exactly 0 nonconforming units is P=0.25.
The probability that the sample will contain exactly 1 nonconforming units is P=0.51.
.
Step-by-step explanation:
We have a sample of size n=4, taken out of a lot of N=12 units, where K=3 are non-conforming units.
We can write the probability mass function as:

where k is the number of non-conforming units on the sample of n=4.
We can calculate the probability of getting no non-conforming units (k=0) as:

We can calculate the probability of getting one non-conforming units (k=1) as:

<span>y = tan^−1(x2/4)</span>
tan(y) = x2/4
sec2(y) = x/2
y′ = xcos^2(y)/2
<span>cos^2(y) = <span>16x2+16</span></span>
<span>y′ = <span>8x/(<span>x2+16)
let u be x2+16
du is 2x dx
dy = 4 du / u
y = 4 ln (</span></span></span>x2 <span>+ 16)
y at x =0 = </span> 4 ln (<span>16) = 11.09</span>