How much pure water must be mixed with 10 liters of a 25% acid solution to reduce it to a 10% acid solution?
2 answers:
Answer:
15 L
Step-by-step explanation:
If x is the liters of pure water, then:
0x + 0.25(10) = 0.10(x + 10)
2.5 = 0.10x + 1
1.5 = 0.10x
15 = x
Answer:
15 L
Step-by-step explanation:
Odyssey ware
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