-3/4x+8=13
-3/4x=5
answer is false
The giraffe (using the ruler) is 11 cm.
1 cm : 50 cm
Multiply both sides by 11.
11 cm : 550 cm
There are 0.01 meters in 1 centimeter.
Multiply 550 cm by 0.01.
(550)(0.01) = 5.5
The giraffe's real length is 5.5 meters.
Answer:
Average: 4
Standard Deviation: 0
Step-by-step explanation:
Because we don't know how each student did we are going to assume that they all got 20% of the questions right
20% of 20 is 4
Which means that we can assume each student got 4 questions correct
Because all entries are the same the standard deviation is 0
Answer:
<em><u>Note: I'm not sure all of this is correct</u></em> O_o
Part A
- Male IQR = Q₃ - Q₁ ≈ 15 - 5 ≈ 10
- Female IQR = Q₃ - Q₁ ≈ 9 - 2 ≈ 7
Part B
- Male Median = Q₂ ≈ 9 to 10
- Female Median = Q₂ ≈ 6 to 7
Difference ≈ 10 - 7 or 10 - 6 ≈ 3 to 4
Part C
<em>Male data distribution</em>
- <u>Shape</u>: The distribution is skewed right.
- <u>Outliers</u>: There doesn't appear to be any clear outliers on the box-plot.
- <u>Center</u>: Because the data is skewed, use median because it's a resistant measure of center. The median appears to be around 9 to 10.
- <u>Spread</u>: Because the data is skewed, use IQR because it's a resistant measure of spread. The IQR is calculated by subtracting the third quartile from the first quartile and appears to be around 10.
<em>Female data distribution</em>
- <u>Shape</u>: The distribution is slightly skewed right, but appears to have more normality than the male distribution
- <u>Outliers</u>: There appears to be one significant outliers at around 30 to 35 that is greatly larger than the rest of the data and is represented as a dot outside the box plot.
- <u>Center</u>: Because the data is skewed, use median because it's a resistant measure of center. The median appears to be around 6 to 7.
- <u>Spread</u>: Because the data is skewed, use IQR because it's a resistant measure of spread. The IQR is calculated by subtracting the third quartile from the first quartile and appears to be around 7.
Median would be a better measure of center for each because both data distributions aren't as symmetric/normal and have a skewed shape. Therefore, the median should be used because of its resistance, as it's not as impacted by extreme values as the mean.
Part D
There doesn't appear to be an outlier in the male dataset, but there appears to be a significantly large outlier in the female dataset, which might mean that there is a significantly large number of females(around 30 to 40) attending the latest superhero movie during a specific day of the study month. This might be due to a discount to the movie ticket that day for females, which attracts large number of females to watch the movie.