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muminat
3 years ago
6

Suppose you do an experiment where you roll a standard die twice. You decide to keep performing this experiment unless you get a

sum of the rolls to be exactly 6. How many times do you feel you have to do this experiment on an average?
Mathematics
1 answer:
zepelin [54]3 years ago
5 0

Answer:

7.2 times

Step-by-step explanation:

There are 36 possible outcomes when rolling a die twice and adding the results. The outcomes for which the sum is 6 are:

Sum = 6: {1,5; 2,4; 3,3; 4,2; 5,1}

Therefore there is a 5 in 36 chance that the sum will be 6.

The expected number of trials to achieve that result is given by:

E = \frac{36}{5}\\E=7.2\ times

On average, it would take 7.2 trials to achieve a sum of 6.

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ε = {x: 2 x 30, x is an integer}, M = {even numbers}, P = {prime numbers}, T = {odd numbers} Find: I) MUP ii) M - T iii) P(MT) i
mariarad [96]

Answer:

Step-by-step explanation:

ε = {x: 2≤ x ≤30}

M = { even numbers} = {2,4,6,8,10,12,14,16,18,20,22,24,26,28,30}

P = { prime numbers} = {2,3,5,7,11,13,17,19,23,29}

T = {odd numbers} = {3, 5, 7, 9, 11,13,15,17,19,21,23,25,27,29}

1. M ∪ P = {2,3,4,5,6,7,8,10,11,12,13,14,16,17,18,19,20,22,23,24,26,28,29,30}

2. M - T =

n(M) - n(T)

15- 14 = 1

3. P(MT)

(MT) = M ∩ T = 0

P ∪ (M ∩ T ) = {2,3,5,7,11,13,17,19,23,29}

4. P' = not a prime number

T' = not odd number = M

P' ∪(M∩T')

P' ∪ {2,4,6,8,10,12,14,16,18,20,22,24,26,28,30}

= {2,4,6,8,9,10,12,14,15,16,18,20,21,22,24,25,26,27,28,30}

6 0
3 years ago
The ages of trees in a forest are normally distributed with a mean of 25 years and a standard deviation of 4. Approximately what
harkovskaia [24]

Answer:

78.88%

Step-by-step explanation:

We have been given that

\mu=25,\sigma=4,x_1=20,x_2=30

The z-score formula is given by

z-\text{score}=\frac{x-\mu}{\sigma}

For x_1=20

z_1=\frac{20-25}{4}\\\\z_1=-1.25

For x_2=30

z_2=\frac{30-25}{4}\\\\z_2=1.25

Now, we find the corresponding probability from the standard z score table.

For the z score -1.25, we have the probability 0.1056

For the z score 1.25, we have the probability 0.8944

Therefore, the percent of the trees that are between 20 and 30 years old is given by

0.8944 - 0.1056

= 0.7888

=78.88%

6 0
4 years ago
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