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Viktor [21]
3 years ago
9

Write the equation in standard form. Y=-1/5x+2

Mathematics
1 answer:
NeX [460]3 years ago
7 0

Answer:

5 x  −  y  =  − 2

Step-by-step explanation:

To write a linear equation in standard form, move each variable term to the left side of the equation and simplify.  This is the formula that you want:

A x  + By = C

Since  x  is on the right side of the equation, switch the sides so it is on the left side of the equation.  Switch the equation around.

5 x  +  2 = y

Move  y  to the left side of the equation because it contains a variable.  Subtract y from both sides or use what's called Subtraction property of equality.

5 x  +  2 −  y  =  0

Move  2  to the right side of the equation because it does not contain a variable.  Subtract 2 from both sides or use what's called Subtraction property of equality.

5 x  −  y  =  − 2

As you can see this version of the equation looks a lot like the formula you want meaning this is correct.

Ax + By = C Replace values ===> 5x - y = − 2

From yours truly to you,

Que.

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Please consider the following values for the variables X and Y. Treat each row as a pair of scores for the variables X and Y (wi
Studentka2010 [4]

Answer:

The Pearson's coefficient of correlation between the is 0.700.

Step-by-step explanation:

The correlation coefficient is a statistical degree that computes the strength of the linear relationship amid the relative movements of the two variables (i.e. dependent and independent).It ranges from -1 to +1.

The formula to compute correlation between two variables <em>X</em> and <em>Y</em> is:

r(X, Y)=\frac{Cov(X, Y)}{\sqrt{V(X)\cdot V(Y)}}

The formula to compute covariance is:

Cov(X, Y)=n\cdot \sum XY-\sum X \cdot\sum Y

The formula to compute the variances are:

V(X)=n\cdot\sum X^{2}-(\sum X)^{2}\\V(Y)=n\cdot\sum Y^{2}-(\sum Y)^{2}

Consider the table attached below.

Compute the covariance as follows:

Cov(X, Y)=n\cdot \sum XY-\sum X \cdot\sum Y

                 =(5\times 165)-(30\times 25)\\=75

Thus, the covariance is 75.

Compute the variance of X and Y as follows:

V(X)=n\cdot\sum X^{2}-(\sum X)^{2}\\=(5\times 226)-(30)^{2}\\=230\\\\V(Y)=n\cdot\sum Y^{2}-(\sum Y)^{2}\\=(5\times 135)-(25)^{2}\\=50

Compute the correlation coefficient as follows:

r(X, Y)=\frac{Cov(X, Y)}{\sqrt{V(X)\cdot V(Y)}}

            =\frac{75}{\sqrt{230\times 50}}

            =0.69937\\\approx0.70

Thus, the Pearson's coefficient of correlation between the is 0.700.

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3 years ago
Anne is choosing a contractor. She has narrowed down her selection to two
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Step-by-step explanation:

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3 years ago
a geometric series where the first term is -12, the last term is -972, and each term after the first is triple the previous term
Luba_88 [7]

Answer:

the geometric series is a(n) = -12(3)^(n-1)

Step-by-step explanation:

"Triple" denotes multiplication by 3.  Thus, the common factor here is 3.

The general formula for a geometric series is a(n) = a(1)(r)^(n-1), where a(1) is the first term, r is the common ratio.

Here, we have a(n)= (-12)(3)^(n-1) = -972.

We need to solve this for n, which represents the last term.

The first step towards solving for n is to divide both sides by -12:

3^(n-1) = 81

To solve for n-1, rewrite 81 as 3^4.  Then we have:

3^(n-1) = 3^4, implying that (n-1) = 4 and that n = 5.

Then we know that it is the 5th term that equals -972.

In summary, the geometric series is a(n) = -12(3)^(n-1).

8 0
3 years ago
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