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Lostsunrise [7]
2 years ago
14

One employee emphasizes the lack of staff as a main stressor affecting the workload. As the number of staff is limited, this rep

resents ________as a source of conflict in organizations.
SAT
1 answer:
storchak [24]2 years ago
5 0

Answer:

Organizational Strategy

Explanation:

One employee emphasizes the lack of staff as a main stressor affecting the workload. As the number of staff is limited, this represents organizational strategy as a source of conflict in organizations.

When employees feel burdened and over-worked due to the strategies that the organizations are trying to implement, they feel repulsive and can form unions against the organizations to change these strategies. This will also effect the outcome and productivity of employees which would reflect on the overall goal of the company.

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A single-platter disk has rotation speed 7200 rpm, number of tracks on one side of platter is 30,000, number of sectors per trac
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Answer:

Rotation Speed = 7200 rpm

No. of tracks on one side of platter = 30000

No. of sectors per track = 600

Seek time for every 100 track traversed = 1 ms

To find:

Average Seek Time.

Average Rotational Latency.

Transfer time for a sector. Total Average time to satisfy a request.

Explanation:

a) As given, the disk head starts at track O. At this point the seek time is 0.

Seek time is time to traverse from 0 to 29999 tracks (it makes 30000)

Average Seek Time is the time taken by the head

to move from one track to another/2

29999 / 2 = 14999.5 ms

As the seek time is one ms for every hundred

tracks traversed. So the seek time for 29,999 tracks traversed is

14999.5/100 = 149.995 ms

b) The rotations per minute are 7200

1 min = 60 sec

7200 / 60 = 120 rotations / sec

Rotational delay is the inverses of this. So 1/120 = 0.00833 sec

= 0.00833 * 100

= 0.833 ms

So there is 1 rotation is at every 0.833 ms

Average Rotational latency is one half the amount of time taken by disk to make one revolution or complete 1 rotation.

So average rotational latency is: 1 / 2r

8.333/2 = 4.165 ms

c) No. of sectors per track = 600

Time for one disk rotation = 0.833 ms

So transfer time for a sector is: one disk revolution time / number of sectors

8.333 / 600 = 0.01388 ms = 13.88 μs

d) Total average time to satisfy a request is calculated as :

Average seek time + Average rotational latency + Transfer time for a sector

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= 154.168 ms

4 0
2 years ago
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