The answer to the question is 1002
Answer:
27 67 16 01 27 35 21 37 74 10
Step-by-step explanation:
Starting from the left, you pick two numbers together and skip two numbers if it is greater than 78.
Meaning:
27816 78416 01822 73521 37741 016312 68000 53645 56644 97892 63408 77919 44575
You pick [27] and leave 81 since it is greater than 78, the population number.
Then you pick [67] and leave 84 as it is also greater than 78.
Then you pick [16] and [01] but leave 82, as it is greater than 78.
Then pick [27], [35], [21], [37], [74] and [10] since they are all less than 78.
At this juncture, you have identified 10 numbers: 27 67 16 01 27 35 21 37 74 10
Answer:
Step-by-step explanation:
Use the info given in the exponential equation to find the value of b, the rate of decay.
where v(t) is the value of the car after a certain number of years, t, have gone by, a is the initial value, and b is the rate of decay. We have everything we need but b:
a = 20000
v(t) = 16000 after t = 1 year:
so
b = .8 Taken in context, this means that the car depreciates 20% each year. Now we can solve the problem being asked of us, which is to find the value of the car after t = 5 years:
which simplifies down a bit to
v(t) = 20000(.32768) so
v(t) = 6553.60, choice C.
Answer:
a. The probability is not equal to 1
b. P (A') = 0.70
c. P ( A U B ) = 0.80
d. P ( A' ∩ B' ) = 0.20
Step-by-step explanation:
a. Because these A and B are disjoint
b. since the probability of A is 0.30 then the probability of A compliment is
P(A compliment ) = 1 - P (A)
P(A compliment ) = 1-0.30
P(A compliment ) = 0.70
c. Since event are disjoint then intersection of A and B is 0, so probability of A U B is;
P ( A U B ) = P (A) + P(B) - P(A∩ B)
P ( A U B ) = 0.30 + 0.50 - 0
P ( A U B ) = 0.80
d. The inetrsection of compilments of A and B are:
by using De Morgan's Law we have,
P ( A' ∩ B' ) = P [(A U B )']
P ( A' ∩ B' ) = 1 - P ( A U B )
P ( A' ∩ B' ) = 1 - 0.80
P ( A' ∩ B' ) = 0.20
