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Butoxors [25]
3 years ago
15

Plz help me really fast

Mathematics
1 answer:
Black_prince [1.1K]3 years ago
5 0
So to get a line parallel to this one you only have to change the y intercept of the first equation. Using that, an equation that represents a line parallel to the first is y = 3x + 7. Hope this helps!
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X is less than or equal to -5
erma4kov [3.2K]

Answer:

x<=-5

Step-by-step explanation:

6 0
3 years ago
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deposits \$700 into an account that pays simple interest at a rate of 6\% per year. How much interest will he be paid in the fir
Virty [35]

Answer:

$210

Step-by-step explanation:

pnr/100

700×6×5/100

$210

5 0
4 years ago
<img src="https://tex.z-dn.net/?f=12x%20%5E%7B2%7D%20%20%2B%204x%20%2B%2020" id="TexFormula1" title="12x ^{2} + 4x + 20" alt="1
Nesterboy [21]
<h3>Answer: </h3>

The GCF is 4

The polynomial factors to 4(3x^2+x+5)

==========================================================

Further explanation:

Ignore the x terms

We're looking for the GCF of 12, 4 and 20

Factor each to their prime factorization. It might help to do a factor tree, but this is optional.

  • 12 = 2*2*3
  • 4 = 2*2
  • 20 = 2*2*5

Each factorization involves "2*2", which means 2*2 = 4 is the GCF here.

We can then factor like so

12x^2 + 4x + 20\\\\4*3x^2 + 4*x + 4*5\\\\4(3x^2 + x + 5)

The distributive property pulls out that common 4. We can verify this by distributing the 4 back in, so we get the original expression back again.

The polynomial inside the parenthesis cannot be factored further. Proof of this can be found by looking at the roots and noticing that they aren't rational numbers (use the quadratic formula).

4 0
3 years ago
Tion?<br>What is/are the given in the problem? What are you going to solve?<br>How can you do​
djverab [1.8K]

Answer:

Not enough information given. Please type the whole question out.

3 0
4 years ago
Write a polynomial of least degree with rational coefficients, a leading coefficient of 1, and zeros at 3 and sqr root 7. Expand
Tresset [83]

Answer:

(x-3)(x^2-7) = x^3 -3x^2 -7x + 21

just change the sign of the root and put x in front of it, then multiply the factors all together

(x-3)(x-sqr7)(x+sqr7)    roots come in conjugate pairs to eliminate irrational coefficients

(x-sqr7)(x+sqr7) = x^2-7.  similar to (a-b)(a+b) = a^2-b^2

Step-by-step explanation:

6 0
3 years ago
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