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3 years ago

What is the decimal number 34.576 written in expanded form?

Mathematics

1 answer:

alekssr [168]3 years ago

8 0

Answer:

Y=34.576 is the answer is expanded

Step-by-step explanation:

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Enter the correct 4 digit code ( no spaces)

Vladimir [108]

Answer:

ABCD= 5934

Step-by-step explanation:

6 0

3 years ago

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Help. What’s the correct answer?

vesna_86 [32]

Answer:

f(g(x)) = -9(sqrt(x + 1) ) + 9

-36

Step-by-step explanation:

This is easier to see if you use the expanded notation.

f(g(x)) = ?

But what that means is that the left most function is f(x) and where every you see an x, you put in a g(x) like so

f(g(x)) = -9(g(x)) + 9 Now substitute the right side of g(x) into the equation for f(x)

f(g(x)) = -9(sqrt(x + 1) ) + 9

Edit to get the numerical answer.

This should be your answer or the expression that will give you the answer.

f(g(24)) = -9(sqrt(24+1) ) + 9

f(g(24)) = -9sqrt(25) +9

f(g(24)) = - 9*5 + 9

f(g(24)) = - 45 + 9

f(g(24)) = - 36

7 0

3 years ago

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A circle is inscribed in a square with a side length of 144. If a point in the square is chosen at random, what is the probabili

____ [38]

Given :

A circle is inscribed in a square with a side length of 144.

So, radius of circle, r = 144/2 = 72 units.

To Find :

The probability that the point is inside the circle.

Solution :

Area of circle,

$A_c = \pi r^2\\\\A_c = 3.14 \times 72^2\ units^2\\\\A_c = 16277.76 \ units^2$

Area of square,

$A_s = (2r)^2\\\\A_s = ( 2 \times 72)^2\ units^2\\\\A_s = 20736\ units^2$

Now, probability is given by :

$P = \dfrac{A_c}{A_s}\\\\P = \dfrac{16277.76}{20736}\\\\P = 0.785$

Therefore, the probability that the point is inside the circle is 0.785 .

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3 years ago

Which of the following best describes the circumference of a circler

Ivanshal [37]

The distance around it

5 0

3 years ago

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(2^8 ⋅ 3^−5 ⋅ 6^0)^−2 ⋅ 3 to the power of negative 2 over 2 to the power of 3, whole to the power of 4 ⋅ 2^28 (5 points) Write y

mihalych1998 [28]

Start by looking at simplifying the smaller problems

anything to the power zero is 1 $6^0 = 1$

next apply the power of a power rule... multiply the powers

$(2^8\times 3^{-5} \times 1 )^{-2} = 2^{8\times -2}\times 3^{-5 \times -2}$

which becomes

$2^{-16}\times 3^{10}$

4 0

3 years ago