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3 years ago

1/2 - 1/5= ???

Mathematics

2 answers:

Aleonysh [2.5K]3 years ago

6 0

Stop asking questons we are pretty much telling you the answer figure it out your self

xxTIMURxx [149]3 years ago

4 0

1/2 - 1/5 =
5/10 - 2/10 = 3/10

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Please helpp with my math hw I’ll give brainlest

-Dominant- [34]

Answer:

20 percent

40 percent

20 percent

20(.008) percent

Step-by-step explanation:

6) 54 - 45 = 9

45 / 9 = 5

100 / 5 = 20

20 percent

7) 60 - 36 = 24

60 / 24 = 2.5

100 / 2.5 = 40

40 percent

8) 30 - 24 = 6

30 / 6 = 5

100 / 5 = 20

20 percent

9) 24.99 - 19.99 = 5

24.99 / 5 = 4.998

100 / 4.998 approx. = 20.008

20.008 percent (or rounded 20 percent)

4 0

2 years ago

Solve for x. Round to the nearest tenth. x =

Nitella [24]

9514 1404 393

Answer:

x ≈ 17.3

Step-by-step explanation:

The triangles are all similar, so the side lengths are proportional.

short side / hypotenuse = x/30 = 10/x

x² = 300 . . . . . . cross multiply

x = 10√3 . . . . . . take square root

x ≈ 17.3

6 0

3 years ago

Let p be "it is raining" and q be "the track meet will be canceled."<br> write p->q in words

trasher [3.6K]

The statement for the logic $\text{p}\rightarrow\text{q}$ is $\fbox{\begin\\\ \text{If it is raining then the track meet will be cancelled}\\\end{minispace}}$

Further explanation:

The logic given in the question is $\text{p}\rightarrow\text{q}$ .

The logic $\text{p}\rightarrow\text{q}$ is a symbol of implication.

Statement p is “It is raining” and the statement q is “The track meet will be canceled”.

The statement formed for the logic $\text{p}\rightarrow\text{q}$ is called a compound statement.

The truth table for the logic $\text{p}\rightarrow\text{q}$ is attached below.

From the table attached below it is observed that there are four cases for the compound statement.

Case1:

If p statement is true and the q statement is true then the compound statement for $\text{p}\rightarrow\text{q}$ is also true.

Case 2:

If p statement is true and the q statement is false then the compound statement for $\text{p}\rightarrow\text{q}$ is false.

Case 3:

If p statement is false and the q statement is true then the compound statement for $\text{p}\rightarrow\text{q}$ is true.

Case 4:

If p statement is false and the q statement is false then the compound statement for $\text{p}\rightarrow\text{q}$ is true.

For a true statement it can also be said that it is a positive statement and for a false statement it can be said that it is a negative statement.

Statement p is given as “It is raining”, which is a positive statement or a true statement.

Statement q is given as “The track meet will be cancelled”, which is a positive statement or a true statement.

As per the table attached for the logic $\text{p}\rightarrow\text{q}$ it is observed that the given statements p and q resembles with the case $1$ as both of the statement are true.

So, the compound statement for $\text{p}\rightarrow\text{q}$ is also a true statement.

The compound statement for the logic $\text{p}\rightarrow\text{q}$ is as follows:

$\fbox{\begin\\\ \text{If it is raining then the track meet will be cancelled}\\\end{minispace}}$

Therefore, the compound statement for the logic $\text{p}\rightarrow\text{q}$ is $\fbox{\begin\\\ \text{If it is raining then the track meet will be cancelled}\\\end{minispace}}$

Learn more:

A problem on composite function brainly.com/question/2142762
A problem on simplification brainly.com/question/894273
A problem in inverse function brainly.com/question/1632445

Answer details

Grade: High school

Subject: Mathematics

Chapter: Logic

Keywords: Logics, implications, compound, compound statement, true statement, false statement, positive statement, negative statement, p->q.

8 0

3 years ago

While watching a movie, Ned, Fred, and Jed shared a bowl of popcorn. Ned ate 1/2 of the popcorn, Fred ate 1/4 of the popcorn, an

Charra [1.4K]

1/8 bowl.
1/2 = 4/8
1/4 = 2/8
1/8 = 1/8

4/8+2/8+1/8 = 7/8
1 - 7/8 = 1/8

6 0

3 years ago

Read 2 more answers

I need help

Mila [183]

<span>5z^2 + 6a

This is because there is an imaginary 1 in front of the second term that you have to remember to use when combining like terms. </span>

7 0

4 years ago