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OLga [1]
4 years ago
11

You might need: Calculator Problem Suppose that Antonia rolls a pair of fair six-sided dice. Let AAA be the event that the first

die lands on 555 and BBB be the event that the sum of the two dice is 666. Using the sample space of possible outcomes below, answer each of the following questions. What is P(A)P(A)P, (, A, ), the probability that the first die lands on 555
Mathematics
1 answer:
melisa1 [442]4 years ago
6 0

Answer:

P(A)=1/6

Step-by-step explanation:

The sample space of the two dice is given below:

[1, 1], [1, 2], [1, 3], [1, 4], [1, 5], [1, 6]

[2, 1], [2, 2], [2, 3], [2, 4], [2, 5], [2, 6]

[3, 1], [3, 2], [3, 3], [3, 4], [3, 5], [3, 6]

[4, 1], [4, 2], [4, 3], [4, 4], [4, 5], [4, 6]

[5, 1], [5, 2], [5, 3], [5, 4], [5, 5], [5, 6]

[6, 1], [6, 2], [6, 3], [6, 4], [6, 5], [6, 6]

n(S)=36

Let A be the event that the first die lands on 5

Sample Space of Event A is:

[5, 1], [5, 2], [5, 3], [5, 4], [5, 5], [5, 6]

n(A)=6

Therefore:

P(A)=n(A)/n(S)

=6/36

=1/6

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igor_vitrenko [27]

Answer:

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Step-by-step explanation:

6 0
3 years ago
Which of the following is a solution of z^5 = 1 + √3 i?
nordsb [41]

Answer:

Option 2 is right

Step-by-step explanation:

Given that

z^5=1+\sqrt{3} i

We can write this in polar form with modulus and radius

|z^5|= \sqrt{1+3} =2\\tan of Angle t =\sqrt{3} \\

Hence angle = 60 degrees and

|z^5|= 2(cos60+isin60)

Since we have got 5 roots for z, we can write 60, 420, 780, etc. with periods of 360

Using Demoivre theorem we get 5th root would be

5th root of 2 multiplied by 1/5 th of 60, 420, 780,....

z= \sqrt[5]{2} (cos12+isin12)\\z=\sqrt[5]{2} (cos84+isin84)\\\\z=\sqrt[5]{2} (cos156+isin156)\\\\z=\sqrt[5]{2} (cos228+isin228)\\\\z=\sqrt[5]{2} (cos300+isin300)\\

Out of these only 2nd option suits our answer

Hence answer is Option 2.

8 0
3 years ago
A slope of −3, passing through the point (15,−50).
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Step-by-step explanation: when a slop is just a number, always put a 1 under it

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3 years ago
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