A survey is taken among customers of a fast-food restaurant to determine preference for hamburger or chicken. Of 200 respondents
1 answer:
Answer:
Hamburger Chicken
Adults 65 60 125
children 55 20 75
120 80 200
a)What is the probability that a randomly selected individual is an adult?
Total no. of adults = 125
Total no. of people 200
The probability that a randomly selected individual is an adult =
b) What is the probability that a randomly selected individual is a child and prefers chicken?
No. of child prefers chicken = 20
The probability that a randomly selected individual is a child and prefers chicken=
c)Given the person is a child, what is the probability that this child prefers a hamburger?
No. of children prefer hamburger = 55
No. of child = 75
The probability that this child prefers a hamburger=
d) Assume we know that a person has ordered chicken, what is the probability that this individual is an adult?
No. of adults prefer chicken = 60
No. of total people like chicken = 80
A person has ordered chicken, the probability that this individual is an adult=
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Percentage of the area shaded = 55%
Solution:
Perimeter of the square = 40 cm
Each side of the square = = 10 cm
Area of the square =
= 10²
= 100
Total area of the square = 100 cm²
The unshaded portion is two triangles.
Base of the smaller triangle = 10 cm – 7 cm = 3 cm
Height of the smaller triangle = 10 cm
Area of the smaller triangle =
Area of the smaller triangle = 15 cm²
Base of the larger triangle = 10 cm – 4 cm = 6 cm
Height of the larger triangle = 10 cm
Area of the larger triangle =
Area of the larger triangle = 30 cm²
Area of the shaded portion = Area of the square – Area of the smaller
triangle – Area of the larger triangle
= 100 cm² – 15 cm² – 30 cm²
Area of the shaded portion = 55 cm²
Percentage of the area shaded =
Percentage of the area shaded = 55%