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Sunny_sXe [5.5K]
4 years ago
13

Define gas exchange and distinguish between a respiratory medium and a respiratory surface

Biology
1 answer:
algol134 years ago
5 0

Answer: Hope this helps

GAS EXCHANGE: the intake of Oxygen and the expulsion of Carbon dioxide. In the capillaries of the alveoli, oxygen travels due to the concentration gradient into those capillaries. Carbon dioxide is then expelled from those capillaries.  

RESPIRATORY MEDIUM: is air for animals and water for fish. It is basically the substance through with living animals receive their oxygen.  

RESPIRATORY SURFACE: is where the gaseous exchange takes place. The oxygen and carbon dioxide move across the respiratory surface entirely by diffusion.

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Will give brainliest plz help I only need help with the 2nd question
Akimi4 [234]

Answer:

Secondary Consumers

Explanation:

If the larvae eat the needles, they are the primary consumers and herbivores. Because they eat the larvae, the birds become the secondary consumer. Tertiary consumers are at the top of the food chain, and eat secondary consumers and primary consumers. Primary producers are energy producing things like plants, etc.

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3 years ago
Which of the following is not a form of passive transport
jeyben [28]
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Cholesterol is a component of cell membranes and is an example of which type of lipid?.
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Cholesterol is a component of cell membranes and is an example of steroid
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how many possible poisoning are reported each year in the united states for children under the age if six?
BaLLatris [955]

Answer:

6.4 poison exposures/1000 population, 37.4 poison exposures in children younger than 6 years/1000 children, 1 poison exposure reported to U.S. poison control centers every 15 seconds.

Explanation:

6 0
3 years ago
Scientist can determine the age of ancient objects by a method called radiocarbon dating. The bombardment of the upper atmospher
IRISSAK [1]

Answer:

3688.323years

Explanation:

Given-

Half life of 14C = 5730years

As we know -

A_{(t)} = A_0e^{kt}

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A_{(t)} = Mass of radioactive carbon after a time period "t"

A_0= initial mass of radioactive carbon

k =radioactive decay constant

t =time

First we will find the value of "k"

\frac{1}{2} = (1)*e^{k*5730}\\

On solving, we get -

e^{5730*k}= 0.5\\5730*k = ln(0.5)\\k = -0.000121

Now, when mass of 14C becomes 64% of the plant  material on earth today, then its age would be

A_{(t)} = A_0*e^{(-0.000121*t)}\\A_{(t)}= 0.64*A_0\\0.64*A_0 = A_0*e-^{(0.000121*t)}\\t = 3688.323years

6 0
3 years ago
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