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DIA [1.3K]
3 years ago
7

Please help me with this math question #6

Mathematics
1 answer:
Sholpan [36]3 years ago
3 0
Cant see the whole thing :P
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UkoKoshka [18]
<h3>Answer:   10*sqrt(30)</h3>

That is the same as writing 10\sqrt{30}

======================================================

Explanation:

The diagram shows that

  • AC = 60
  • AD = 50

That must mean DC = AC-AD = 60-50 = 10

We'll use this to help find BD as shown below

AD/BD = BD/DC

AD*DC = BD*BD .... cross multiply

(BD)^2 = AD*DC

BD = sqrt(AD*DC) ..... geometric mean formula

BD = sqrt(50*10)

BD = sqrt(500)

----------------------

Now apply the pythagorean theorem to find AB. Focus on triangle ABD.

(AD)^2 + (BD)^2 = (AB)^2

(AB)^2 = (AD)^2 + (BD)^2

(AB)^2 = (50)^2 + (sqrt(500))^2

(AB)^2 = 2500 + 500

(AB)^2 = 3000

AB = sqrt(3000)

AB = sqrt(100*30)

AB = sqrt(100)*sqrt(30)

AB = 10*sqrt(30)

8 0
3 years ago
Graph the function f(x)= -5(x+5)^2–4.
irina1246 [14]

Answer:

Vertex= (-5,-4)

Another point=(0, -129)

Step-by-step explanation:

The vertex is also the maximum, and the point is also the y-intercept.

3 0
3 years ago
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