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Answer: 12/25</h3>
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Reason:
60% = 60/100 = 0.6 is the probability of making any given free-throw.
1 - 0.6 = 0.4 is the probability of missing any given free-throw.
We have these probabilities
- A = P(making 1st, missing 2nd) = 0.6*0.4 = 0.24
- B = P(missing 1st, making 2nd) = 0.4*0.6 = 0.24
The probability of making exactly one free throw is A+B = 0.24+0.24 = 0.48
Convert this to a fraction:
0.48 = 48/100 = (4*12)/(4*25) = 12/25
Answer:10
Step-by-step explanation:
2+4+6+6+9+13+30=70
70 divided by 7= the mean should be 10
We let the number of years that the two jobs will have the same payment be denoted as t. Equating the wages of these two jobs after t - 1 years will give us an equation of,
22,000 + 4000(t -1) = 26,000 + 2000(t - 1)
The value of t from the generated equation is 3. Therefore, after 3 years the jobs will be paying the same wages.
The list is needed in order to solve the problem, Im sorry but I can’t do anything with this information
Answer:
26*26*26 = 17576 ways to select 3 letters
10*10= 100 ways to select 2 numbers
So then the total number of ways are:
possible ways
Step-by-step explanation:
For this case we assume that we have 26 letters from A to Z and 10 numbers from 0 to 9 .
And we want to calculate the number of possible passwords possible if the password consists of 3 letters followed by 2 digits.
And for this case we can use the multiplication principle of combinatories, since we don't have any restriction about the letters of the numbers we can have repetition of letters or numbers.
For the number of possible letters:
26*26*26 = 17576 ways to select 3 letters
10*10= 100 ways to select 2 numbers
So then the total number of ways are:
possible ways
