Well, Brainly really doesn't like questions that are lifted straight out of exams, tests, or quizzes, so there's only so much I can say.

... You've GOT the formula for the height h at any time t .

... It TELLS you to find t when h=0.

... So write the equation

-16 t^2 + 32 t = 0

and then solve the equation to find t .

You'll find two solutions for t .
One of them is. t=0 .
This reveals the mind-blowing fact that the instant before the rocket was launched, at t=0, the rocket was on the ground.
The other solution for t will tell you how many seconds after launch the rocket is back on the ground.

5 0

2 years ago

Find the gradient of the function at given point. f(x,y)=ln(x^2+y^2)

N76 [4]

$\nabla f(x,y)=\left\langle\dfrac{\partial f}{\partial x},\dfrac{\partial f}{\partial y}\right\rangle=\left\langle\dfrac{2x}{x^2+y^2},\dfrac{2y}{x^2+y^2}\right\rangle$

You didn't provide the "given point", but I assume you're capable of plugging it in.

5 0

2 years ago

triangle abc has vertices at a(-2 3),B(0,3),c(-1,-1). Find the coordinates of the image after a reflection over the x-axis.

Crazy boy [7]

The new coordinates of the triangle after reflection from x-axis would be A(-2, -3) , B(0, -3) and C( -1, 1 )

<u>Explanation:</u>

The vertices of the triangle are A(-2 3), B(0,3), C(-1,-1)

The reflection is over the x-axis.

When the reflection is along the x-axis, the coordinates of x does not change. However, the coordinates of y does change.

The negative value of y becomes positive and the positive value of y becomes negative.

Similarly,

A(-2, 3) would become A(-2, -3)

B(0, 3) would become B(0, -3)

C(-1, -1) would become C( -1, 1 )

Therefore, the new coordinates of the triangle after reflection from x-axis would be A(-2, -3) , B(0, -3) and C( -1, 1 )

6 0

2 years ago

Cu cît este mai mic împatritul lui63 fata de înnoitul rasturnatului sau?

never [62]

Indeed you need to speech English

4 0

2 years ago