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jasenka [17]
3 years ago
13

Where is the hole for the following function located f(x)= x+3/(x-4)(x+3)

Mathematics
2 answers:
Marizza181 [45]3 years ago
6 0
In a rational function, holes are located where f(x) is undefined(the denominator is 0), but the undefined points can be factored out. In f(x), when x is 4 or -3, f(x) is undefined. But, x+3 can be factored out, so it is a hole. The hole is located at (-3,-1/7)
dangina [55]3 years ago
3 0
The hole is located at x=-3
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Step-by-step explanation:

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For example, a line of the form y=-3x+2 can be termed as the line of an equation in slope-intercept form after comparing with it.

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How to simplify 4(2a)+7(-4b)+(3×c×5)
maw [93]
→ Solutions

⇒ Simplify <span><span><span>4<span>(<span>2a</span>)</span></span>+<span>7<span>(<span>−<span>4b</span></span>)</span></span></span>+<span><span>3c</span><span>(5)</span></span></span><span>⇒ </span><span><span><span><span><span>8a</span>+</span>−<span>28b</span></span>+<span>15<span>c

Answer
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ad-work [718]

Answer:

x<_2

Step-by-step explanation:

first off solve this like a regular equation the >_ dosent matter till later

so basically first multiply - by 13 and -x so you get -13 and x (multiplying two negatives = a positive)

so its 5x-13+x>_9x-7

add 5x and x to get 6x-13 on one side

then you get 6x-13>_9x-7 then subtract -9x from both sides

so its now -3x-13>_-7 add 13 so you get -3x>_6

then divide both sides by -3 (when you divide an equation with a >< or <_ >_ by a negative number that sign switches) so it will now be x<_2

that your final answer hope this helps :)

6 0
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