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tensa zangetsu [6.8K]
3 years ago
5

Find the standard form of the equation of the ellipse with the given characteristics.

Mathematics
1 answer:
kicyunya [14]3 years ago
8 0
So hmm if you notice the picture below

between 2 and 16, there are 14 units, so, the center is half-way in between, thus, is at y = 7, or -2, 7

because, the major axis is over the y-axis, then the "a" component, goes under the fraction with the "y" in the numerator

\bf \textit{ellipse, vertical major axis}\\\\

\cfrac{(x-{{ h}})^2}{{{ b}}^2}+\cfrac{(y-{{ k}})^2}{{{ a}}^2}=1
\qquad center\ ({{ h}},{{ k}})\qquad
 vertices\ ({{ h}}, {{ k}}\pm a)\\\\
-----------------------------\\\\

\begin{cases}
b=4\\
a=7\\
h=-2\\
k=7
\end{cases}\implies \cfrac{(x+2)^2}{4^2}+\cfrac{(y-7)^2}{7^2}\implies \cfrac{(x+2)^2}{16}+\cfrac{(y-7)^2}{49}

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