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Makovka662 [10]
3 years ago
5

Use the work shown below to write the equation for a line that has a slope of Negative two-fifths and passes through (15, –2). y

= mx + b 1. Substitute the known values: negative 2 = negative two-fifths (15) + b. 2. Solve for b: negative 2 = negative 6 + b. b = 4. What is the equation of the line in slope-intercept form? Negative 2 = negative two-fifths x + 4 y = negative two-fifths (15) + 4 y = negative two-fifths x minus 4 y = negative two-fifths x + 4
Mathematics
1 answer:
grin007 [14]3 years ago
3 0

Answer:

  • y = -2/5x + 4, the last option

Step-by-step explanation:

<u>The formula:</u>

  • y = mx + b

<u>The steps:</u>

  • 1. -2 = (-2/5)(15) + b
  • 2. -2 = -6 + b
  • 3. b = 6 - 2
  • 4. b = 4

<u>The result</u>

  • y = -2/5x + 4

===========================================================

<u>What is the equation of the line in slope-intercept form? </u>

  • Negative 2 = negative two-fifths x + 4
  • y = negative two-fifths (15) + 4
  • y = negative two-fifths x minus 4
  • <u>y = negative two-fifths x + 4</u>
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