Use the work shown below to write the equation for a line that has a slope of Negative two-fifths and passes through (15, –2). y

Question

3 years ago

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Use the work shown below to write the equation for a line that has a slope of Negative two-fifths and passes through (15, –2). y

= mx + b 1. Substitute the known values: negative 2 = negative two-fifths (15) + b. 2. Solve for b: negative 2 = negative 6 + b. b = 4. What is the equation of the line in slope-intercept form? Negative 2 = negative two-fifths x + 4 y = negative two-fifths (15) + 4 y = negative two-fifths x minus 4 y = negative two-fifths x + 4

Mathematics

1 answer:

grin007 [14] · Answer 1 · 2022-09-18T21:44:31+03:00

Answer:

y = -2/5x + 4, the last option

Step-by-step explanation:

The formula:

y = mx + b

The steps:

1. -2 = (-2/5)(15) + b
2. -2 = -6 + b
3. b = 6 - 2
4. b = 4

The result

y = -2/5x + 4

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What is the equation of the line in slope-intercept form?

Negative 2 = negative two-fifths x + 4
y = negative two-fifths (15) + 4
y = negative two-fifths x minus 4
y = negative two-fifths x + 4