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DochEvi [55]
3 years ago
13

If I paid $12 an hour and I work 12 hours and 18 minutes. How much money did I earn that day ?

Mathematics
2 answers:
shtirl [24]3 years ago
8 0

I will earn $147.6 that day.

velikii [3]3 years ago
6 0

Answer:146.16

Step-by-step explanation:

$12.00×12 hours=$144.00

$12.00×.18 minutes=$2.16

$144.00+2.16=$146.16

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Expand and simplify (x-2)(2x+4)
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Answer:

2 {x}^{2}  - 8

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7 0
2 years ago
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Find the median of the following numbers. 14, 17, 21, 28, 40. ​
Elis [28]

Answer:21

Step-by-step explanation: The median is the number in the middle sorted from least to greatest, here 21 is the middle number.

4 0
3 years ago
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Consider the numbers 4/15 and 3/10 (a) Compare the numbers. (B) find a fraction between the two given numbers
valentinak56 [21]
As a decimal 4/15 = 0.2666667
As a decimal 3/10 = 0.3 [talk about close]
3/10 is bigger.

You could take an average to find something between 4/15 and 3/10
1/2(4/15 + 2/10)
1/2(8/30 + 6/30)
1/2(14/30)
1/2(7/15)
7/30 is between the two given numbers..
5 0
3 years ago
Please answer! I crossed out the ones you don’t have to complete.
Nina [5.8K]

Answer:

1. Rewriting the expression 5.a.b.b.5.c.a.b.5.b using exponents we get: \mathbf{5^3a^2b^4c}

5.  x^-6 = \frac{1}{x^6}

6. 5^{-3}.3^{-1}=\frac{1}{5^3.3^1}

7. a^{-3}b^0c^4=\frac{c^4}{a^3}

Step-by-step explanation:

Question 1:

We need to rewrite the expression using exponents

5.a.b.b.5.c.a.b.5.b

We will first combine the like terms

5.5.5.a.a.b.b.b.b.c

Now, if we have 5.5.5 we can write it in exponent as: =5^{1+1+1}=5^3

a.a as a^{1+1}=a^2

b.b.b.b as: b^{1+1+1+1}=b^4

So, our result will be:

5^3a^2b^4c

Rewriting the expression 5.a.b.b.5.c.a.b.5.b using exponents we get: \mathbf{5^3a^2b^4c}

Question:

Rewrite using positive exponent:

The rule used here will be: a^{-1}=\frac{1}{a^1} which states that if we need to make exponent positive, we will take it to the denominator.

Applying thee above rule for getting the answers:

5) x^{-6} = \frac{1}{x^6}

6) 5^{-3}.3^{-1}=\frac{1}{5^3.3^1}

7) a^{-3}b^0c^4=\frac{b^0c^4}{a^3}

We know that b^0=1 so, we get

a^{-3}b^0c^4=\frac{b^0c^4}{a^3}=\frac{c^4}{a^3}

4 0
3 years ago
Given any two numbers, which is greater, the lowest common multiple of the numbers or the greatest common multiple?
tester [92]

After you've calculated a least common multiple, always check to be sure your answer can be divided evenly by both numbers. Find the LCM of these sets of numbers. Multiply each factor the greatest number of times it occurs in any of the numbers. 9 has two 3's, and 21 has one 7, so we multiply 3 two times, and 7 once.

4 0
3 years ago
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