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Inessa05 [86]
4 years ago
8

What is the next term in the pattern 2, 9, 11, 20, 31, ...? a.42 b.51 c.53 d.82

Mathematics
2 answers:
zhenek [66]4 years ago
8 0
The answer is B.) 51

plz mark me as brainliest and thank me, it motivates me to answer more of your questions :)
Alisiya [41]4 years ago
3 0
Correct answer is 
31+20=51 (B)
2+7=9
9+2=11
11+20=31

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Sammy has 4 bags of marbles. Each bag has 12 marbles in it. Which equation represents how many total marbles he has
kumpel [21]

Answer:

t = 4 x 12

Step-by-step explanation:

t = total # of marbles

Equation: t = 4 x 12

=48

4 0
3 years ago
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Find the circumference of a circle with a radius of 18.5m, give answers in pie
Simora [160]

Answer:

C = pi * 37m

Step-by-step explanation:

Diameter = 2(18.5m) = 37m

5 0
3 years ago
If she wants to track to have a circumference of 150 feet , what does the radius of the track need to be?
Gemiola [76]

Solution:

we are given that

she wants to track to have a circumference of 150 feet.

we have been asked to find

what does the radius of the track need to be?

As we know that

Circumference=2\pi r

Substitute the values we get

150=2 \pi r\\
\\
r=\frac{75}{\pi} \\
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r=\frac{75}{22/7}\\
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6 0
3 years ago
PLEASE ANSWER NOT THAT HARD IM JUST DUMM
Luden [163]

Answer:

They can make 64 bags with bubbles and gummy bears

Step-by-step explanation:

8 0
3 years ago
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Consider the matrix shown below:
velikii [3]

Answer:

A)\ \ \ \ \left[\begin{array}{ccc}8&-5\\-3&2\\\end{array}\right]

Step-by-step explanation:

Given the matrix: \left[\begin{array}{ccc}2&5\\3&8\\\end{array}\right],  it's inverse is calculated using the formula:

\left[\begin{array}{ccc}a&b\\c&d\\\end{array}\right]^{-1}=\frac{1}{det\left[\begin{array}{ccc}a&b\\c&d\\\end{array}\right] }\left[\begin{array}{ccc}d&-b\\-c&a\\\end{array}\right]

#Therefore, we calculate as;

\frac{1}{det\left[\begin{array}{ccc}2&5\\3&8\\\end{array}\right] }\left[\begin{array}{ccc}8&-5\\-3&2\\\end{array}\right] \\\\\\\\\#det\left[\begin{array}{ccc}2&5\\3&8\\\end{array}\right] =1\\\\\\\\=\frac{1}{1}\left[\begin{array}{ccc}8&-5\\-3&2\\\end{array}\right] \\\\\\\\=\left[\begin{array}{ccc}8&-5\\-3&2\\\end{array}\right]

Hence, the inverse of the matrix is \left[\begin{array}{ccc}8&-5\\-3&2\\\end{array}\right]

8 0
3 years ago
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