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lord [1]
3 years ago
15

PLS HELP M ASAP FOR (8) A and B (SHOW WORKK!!!) +LOTS OF POINTS!

Mathematics
1 answer:
marissa [1.9K]3 years ago
3 0
The first part to question 8 is 2.25 and the answer to part b is 12
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PLEASE PLEASE PLEASE HELP
Eduardwww [97]

first make two triangles using M , so there iwll be 90-45-45, and 30-60-90 then use the side rules of those special triangles

6 0
3 years ago
HELP ME PLEASE ASAP!!!!
Naddika [18.5K]

Answer:

A = 22.62

Step-by-step explanation:

Remember law of tan

tan = opposite/adjacent

tan (A) = 5/12

A= tan inverse ( 5/12)

A = 22.62

6 0
3 years ago
Can someone help me on all of these
lisov135 [29]

Answer:

See below!

Step-by-step explanation:

Ⓗⓘ ⓣⓗⓔⓡⓔ

Yes!

1) Centre

2) Radius {Plural: Radii}

3) Diameter

4) Arc

5) Pi is the ratio of a circle's circumference to its diameter

6) 3.14

7) 6m

8) 7 in

(っ◔◡◔)っ ♥ Hope this helped! Have a great day! :) ♥

Please, please give brainliest, it would be greatly appreciated, I only a few more before I advance, thanks!

7 0
3 years ago
Read 2 more answers
A jewelry store marks up the price of bracelets they purchase at $30.00 each by 75%. What is the markup and new price of each br
horrorfan [7]
The new price is 52.50
30x2=60
30/4=7.5
7.5x3=22.5
22.50+30= 52.50
3 0
3 years ago
Simplify.Your answer should contain only positive exponents.
zhannawk [14.2K]

Step-by-step explanation:

1) r^3r^3

\mathrm{Apply\:exponent\:rule}:\quad \:a^b\cdot \:a^c=a^{b+c}

=r^{3+3}

=r^6

2) 3k^3k^3

\mathrm{Apply\:exponent\:rule}:\quad \:a^b\cdot \:a^c=a^{b+c}

=3k^{3+3}

=3k^6

3) \left(3b^2\right)^3

\mathrm{Apply\:exponent\:rule}:\quad \left(a\cdot \:b\right)^n=a^nb^n

=3^3\left(b^2\right)^3

=27\left(b^2\right)^3

=27b^6

4) \left(2m^3\right)^3

\mathrm{Apply\:exponent\:rule}:\quad \left(a\cdot \:b\right)^n=a^nb^n

=2^3\left(m^3\right)^3

=8\left(m^3\right)^3

=8m^{3\cdot \:3}

=8m^9

5) \frac{3r^3}{r^2}

\mathrm{Apply\:exponent\:rule}:\quad \frac{x^a}{x^b}=x^{a-b}

=3r^{3-2}

=3r^1

=3r

3 0
3 years ago
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