Answer: ∠B = 50°
∠BCD = 40°
<u>Step-by-step explanation:</u>
ACB is a right triangle where ∠A = 40° and ∠C = 90°.
Use the Triangle Sum Theorem for ΔABC to find ∠B:
∠A + ∠B + ∠C = 180°
40° + ∠B + 90° = 180°
∠B + 130° = 180°
∠B = 50°
BCD is a right triangle where ∠B = 50° and ∠D = 90°.
Use the Triangle Sum Theorem for ΔBCD to find ∠C:
∠B + ∠C + ∠D = 180°
50° + ∠C + 90° = 180°
∠C + 140° = 180°
∠C = 40°
Answer:
A=23512.32
Step-by-step explanation:
The equation for the area of a cylinder is A=2πrh+2πr^2
If we substitute the radius and height, the equation would be A=2π(60)(2.4)+2π(60)^2
π can be shortened to 3.14 so it's A=2(3.14)(60)(2.4)+2(3.14)(60)^2
We're left with 904.32+22608
So the answer is 23512.32
Step-by-step explanation:
10^2 = 100
10^-2 = 1/100 ➡ 0.01
Using the triangle, we can find the angle lengths and using those and trig ratios, find the side lengths. Lets say the top side length is "y".
Using the Law of triangles, we can find the missing angle from 180-90-70=20 deg.
Then we can use the Law of sines,
sin(70)/13=sin(20)/y
y=sin(20)*13/sin(70)
y=15.34
Finally, we use the Pythagorean Theorem, (13)^2+(15.34)^2=x^2
x = 20.1
152700 is answer. Try to do these problems on paper then you can see where you went wrong . also try to do the actual question
