Answer:
0.1460
Explanation:
Total population size= 411 + 911 + 800 = 2122
Let's assume that the population is in Hardy Weinberg Equilibrium.
Under these conditions, frequency of recessive allele (a)= 911 x 2 + 800 / 2122 x 2 = 2622/4244= 0.6178
.
This is because each homozygous recessive genotype has two copies of the recessive allele while each heterozygous dominant genotype has one copy of the recessive allele.
For this population to be under Hardy Weinberg Equilibrium, frequency of dominant allele (A) = 1- 0.6178= 0.3822
Frequency of homozygous dominant genotype (AA) = 0.1460
Answer:
Spectrophotometer that measures between 100 and 900 nanometers.
Explanation:
dont quote me on this
Answer:
++
Explanation:
This is an example of ecological interaction where the actions of one organism is benefitting the other i.e. both organisms are benefitting from the relationship. This type of relationship is referred to as MUTUALISM.
In this example, the cellulose-digesting organism lives in the guts of the termite. The termite benefits from this association by getting its ingested cellulose (in form of wood) degraded or broken down. Termites feed on wood and naturally, they don't contain the enzymes that helps it digest it, hence, they depend on the enzyme secreted by these organisms in their guts to digest cellulose.
The cellulose-digesting organism gets shelter, protection and food in return as they cannot survive outside the termite's guts. Hence, it is a win-win (++) situation for the two organisms.
Answer:
Nucleoid
Explanation:
I just know by studying cells
The answer is A. You are welcome have a nice day
