The nearest tenth of how fast a rover will hit Mars' surface after a bounce of 15 ft in height is 20.7ft/s.
<h3>What is the approximation about?</h3>
From the question:
Mars: F(x) = 2/3
Therefore, If x = 15
Then:
f (15) = 2/3
= 16/3
= 20.7ft/s
Hence, The nearest tenth of how fast a rover will hit Mars' surface after a bounce of 15 ft in height is 20.7ft/s.
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Answer:
N = 4.33
Step-by-step explanation:
2N + 7 = 5N - 6
3N = 13
N = 13/3
N = 4.33
5/10x10/3
Simplifies to:
1/2x10/3
this equals to
10/6 which simplifies to 5/3
5/3 is your answer
Answer:
6.oz and all other things are going on
Step-by-step explanation:
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