- Move vertex A so that BAD is a
1 answer:
You might be interested in
Answer:
The required point is P(-7,) where, x-coordinate twice the y-coordinate on line 2x - 6y = 7
Step-by-step explanation:
Given equation of line is 2x-6y=7
To find point on graph whose x-coordinate twice the y-coordinate:
Let y be y-coordinate of point
Hence, x-coordinate of point will be 2y
The required point is P(2y,y) on equation of line 2x-6y=7
Now,
2x-6y=7
2(2y)-6y=7
-2y=7
y=
Thus,
The required point is P(-7,)
Note: Figure show equation of line red line and point P as blue dot.
Check the picture below.
so, as you see there, those radius make out an "equilateral triangle", and as you know, all angles in an equilateral triangle are 60° each.
now, if we make out the other equilateral triangle underneath that one, and add up the angles making out ∡CBD, you'd get, yes, you guessed it.
so, as you see there, those radius make out an "equilateral triangle", and as you know, all angles in an equilateral triangle are 60° each.
now, if we make out the other equilateral triangle underneath that one, and add up the angles making out ∡CBD, you'd get, yes, you guessed it.