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creativ13 [48]
3 years ago
5

The scale of the map is missing.the actual distance from liberty to west quall is 72 miles,and it is 7 inches on the map.

Mathematics
2 answers:
storchak [24]3 years ago
4 0
Scale = 72/7 = 10 2/7 miles per inch

(7-4) x 10 2/7 = 30.857142....miles from west quall
Tom [10]3 years ago
4 0

Answer:

a)  1 inches=  \frac{72}{7} miles

b)  30.86 miles

Step-by-step explanation:

a) Given: Distance from liberty to west quall is 72 miles and it is 7 inches on the map.

To find : The scale on the map.

So, In 7 inches distance covered = 72 miles

In 1 inches distance covered= \frac{72}{7}

Therefore, The scale on the map is

1 inches=  \frac{72}{7} miles.

b) Given: Foston is between liberty and west quall and is 4 inches from liberty on the map.

To find : Distance between foston to west quall (F to W)        

We know the scale of map i.e.  1 inches=  \frac{72}{7} miles.

Firstly, we find the distance covered from liberty to foston i.e. 4 inches on the map

4 inches =  4\times\frac{72}{7} miles

4 inches = 41.14 miles

Now the distance between liberty to west quall (L to W)= 72 miles

and the distance between liberty to foston (L to F)= 41.14 miles

Therefore, the distance between foston to west quall(F to W)=distance(L to W)- distance(L to F) (Refer the attached graph)

Distance(F to W)= distance(L to W)- distance(L to F)

Distance(F to W)=72-41.14 miles = 30.86 miles  

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