The answer is A because all of the coordinates match to the points up above. Lets take the coordinate (-3,6) for example. -3 would be where the point is on the x-axis which is horizontal (side to side), that means the 6 would be on the y-axis vertical(up and down). Hope this helps :)
Rt-3f=12 subtract rt from both sides
-3f=12-rt divide both sides by -3
f=(rt-12)/3
Answer:
11:54pm
Step-by-step explanation:
Key details in the Question:
- Starting at 11:00 pm a bus makes a stop every 27 minutes.
- starting at 11:00pm a taxi makes a stop every 18 minutes.
The task is to find the time in which both the bus and taxi would make a stop.
Since the taxi has the shorter duration for a stop, we would use it as the basis for our calculations.
During the first taxi stop - 11:18pm
The Bus has not yet made its stop.
During the second taxi stop - 11:36pm
The Bus has made it's first stop (11:27pm) but is currently on the road.
During the third taxi stop - 11:54pm
The Bus would also be making it's second stop
Let's call this unknown number, x.
So then we can put together the equation using the information from the question:
![10*(\frac{1}{2}*x+6)=8](https://tex.z-dn.net/?f=%2010%2A%28%5Cfrac%7B1%7D%7B2%7D%2Ax%2B6%29%3D8%20%20)
Then we start by distributing this 10 to both the
and the 6:
![5x+60=8](https://tex.z-dn.net/?f=%205x%2B60%3D8%20)
Then we subtract 60 on both sides:
![5x=-52](https://tex.z-dn.net/?f=%205x%3D-52%20)
Then we divide both sides by 5 to solve for x:
or ![-10\frac{2}{5}](https://tex.z-dn.net/?f=%20-10%5Cfrac%7B2%7D%7B5%7D%20%20)
Assuming you mean y=10x+150 and y=20x+115, you need to use a simultaneous equation, because you have two equations with two unknowns (x and y)
rearrange so
10x-y=-150
20x-y=-115
multiply the top by -1, so that if we add the two lines together, the y will cancel out
-10x+y=150
20x-y=-115
add the two lines together
10x=35
x=3.5
so the time is 3 and a half weeks
then we can sub in x to find y
20x-y=-115
20(3.5)-y=-115
70-y=-115
-y=-185
y=185
so 185 tickets were sold !
you can sub these values into your original equations to check your answer :)