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Ghella [55]
3 years ago
8

The graph models the height of a diver above water, in feet, x seconds after jumping off a springboard. What does the x-intercep

t represent?
The diver reached the maximum jump height after 2 s.
The springboard was 2 ft above the surface of the water.
The diver jumped 2 ft above the springboard.
The diver was in the air for 2 s.
Mathematics
1 answer:
Tom [10]3 years ago
7 0
Your answer would be D I took the quiz just now and got a 100% :) 
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Write an equation of a line that has a slope of -2 and passes through the point (1,4)
RoseWind [281]

Answer:

y = -2x + 6

Step-by-step explanation:

Since we already have the slope we just need to find the y-intercept.

To do that just plug in the point you were given. (1,4)

4 = -2(1) + b (b represents the y-intercept)

4 = -2 + b (add 2 on both sides)

6 = b

y = -2x + 6 is the equation

Hope this helps!!

3 0
3 years ago
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M(6, 6) is the midpoint of segment RS. The coordinates of S are (8, 9). What are the coordinates of R?
weqwewe [10]
(4,3) Down 3 from 6 on y-axis and left 2 on x-axis.
3 0
3 years ago
The product of 11 and n
castortr0y [4]

Answer:

11n

Step-by-step explanation:

(11)(n) =11n

8 0
3 years ago
Read 2 more answers
{ HARDER }
cestrela7 [59]
(i):
x = Vtcos\theta
Vcos\theta = \frac{x}{t}

y = -\frac{1}{2}gt^{2} + Vtsin\theta
Vsin\theta = \frac{y + \frac{1}{2}gt^{2}}{t}

V^{2}cos^{2}\theta + V^{2}sin^{2}\theta = \frac{x^{2}}{t^{2}} + \frac{y^{2} + gt^{2}y + \frac{1}{4}g^{2}t^{4}}{t^{2}}
V^{2} = \frac{x^{2}}{t^{2}} + \frac{y^{2} + gt^{2}y + \frac{1}{4}g^{2}t^{4}}{t^{2}}
t^{2}V^{2} = x^{2} + y^{2} + gt^{2}y + \frac{1}{4}g^{2}t^{4}
4t^{2}V^{2} = 4x^{2} + 4y^{2} + 4gt^{2}y + g^{2}t^{4}
4x^{2} + 4y^{2} + 4gt^{2}y + g^{2}t^{4} - 4t^{2}V^{2} = 0
4y^{2} + 4gt^{2}y + (gt^{2}t^{4} + 4x^{2} - 4t^{2}V^{2}) = 0

(ii): Impact is when x = d.
\text{Impact: } d = Vtcos\theta
t = \frac{d}{Vcos\theta}

First impact occurs when t is minimised.
This means that Vcos theta is maximised, which means cos theta = 1, and theta = 0
\therefore \text{First impact occurs at } \theta = 0\text{: }t = \frac{d}{V(1)} = \frac{d}{V}

i'll do the rest later.
8 0
3 years ago
How is the degree of a polynomial related to the concept of complex numbers?
aliya0001 [1]

The Fundamental Theorem of Algebra states that any constant-coefficient single-variable polynomial of degree n has (counting multiplicity) n complex roots (Real numbers are a subset of Complex numbers).


_____

Especially for higher-degree polynomials, some roots may not be real. Certainly, if the polynomial has complex coefficients (having an imaginary part), at least one root will be complex (have an imaginary part). That is, the only way you can find the roots is to admit the existence of complex numbers. One simple example is ...

... x^2 +1 = 0

3 0
3 years ago
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