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3 years ago

Please help me please lots of points

Mathematics

2 answers:

Anuta_ua [19.1K]3 years ago

6 0

The answer in scientific notation would be 5×10^1 Which is 50 in standard notation

To get this you first look for you two numbers which are 1*10^21 and 5*10^22

However a key word in this word problem is how many times greater than

When you see this, you will divide so 1×10^21 ÷ 5×10^22 = 5×10^1

When you have your answer to convert it into standard notation you just add one 0 to the 5 giving you 50, because its only to a power of 1

Therefore, the diameter of the IC 1101 is 50 times greater than the diameter of the Milky way

tigry1 [53]3 years ago

5 0

uhh as each scientific notation is 10 more, so therefore 5 x 10

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Answer:

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$V(t)=14550e^{-0.158t$

$\frac{dV(t)}{dt} =\frac{d}{dt}14550e^{-0.158t$

$\frac{dV(t)}{dt} =14550 \frac{d}{dt}e^{-0.158t$

$\\Let u= -0.158t,\frac{du}{dt}=-0.158$

$\frac{dV(t)}{dt} =14550 \frac{d}{du}e^u\frac{du}{dt}$

$\frac{dV(t)}{dt} =14550 X -0.158 e^{-0.158t}=-2298.9e^{-0.158t}$

In 2019, i.e. 2 years after, t=2

The rate of change of the value

$\frac{dV(t)}{dt} =-2298.9e^{-0.158X2}$

= $\frac{dV(t)}{dt} =-2298.9e^{-0.316}$ = - 1675.38

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