Explain how you can use the terms from the binomial expansion to approximate 0.985.
1 answer:
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Answer:
45 minutes
Step-by-step explanation:
Assume task completed in total x hours
So q will take 45 more minutes
Answers:
a = -6/37
b = -1/37
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Explanation:
Let's start things off by computing the derivatives we'll need
Apply substitution to get
I've factored things in such a way that we have something in the form Msin(x) + Ncos(x), where M and N are coefficients based on the constants a,b.
The right hand side is simply sin(x). So we want that cos(x) term to go away. To do so, we need the coefficient (a-6b) in front of that cosine to be zero
a-6b = 0
a = 6b
At the same time, we want the (-6a-b)sin(x) term to have its coefficient be 1. That way we simplify the left hand side to sin(x)
-6a -b = 1
-6(6b) - b = 1 .... plug in a = 6b
-36b - b = 1
-37b = 1
b = -1/37
Use this to find 'a'
a = 6b
a = 6(-1/37)
a = -6/37
De Moivre's Theorem states that if a complex number is written in the polar coordinate form [ r (cosθ + 
sinθ)] and you raise it to the power n, then this can be evaluated by raising the modulus (r) to the power and multiply the argument (θ) by the power. This therefore would give r ⁿ [cos (nθ) + sin (nθ)].
let A = ∛ <span>(8 cos (4π / 5) + 8 i sin (4π / 5))
</span>⇒ A = ∛ <span>(8 [cos (4π / 5) + i sin (4π / 5)])
</span>
Now by applying De Moivre's Theorem,
⇒ A =
[cos (
× 
) + sin ( × )
⇒ A = 2 [ cos (
) + sin ()
⇒ A = 2 [0.0117 + 0.01297 ] rads
let A = ∛ <span>(8 cos (4π / 5) + 8 i sin (4π / 5))
</span>⇒ A = ∛ <span>(8 [cos (4π / 5) + i sin (4π / 5)])
</span>
Now by applying De Moivre's Theorem,
⇒ A =
⇒ A = 2 [ cos (
⇒ A = 2 [0.0117 +